Answer:
The second wavelength is 482 nm.
Explanation:
Given that,
Wavelength = 630 nm
Distance from central maxim = 0.51 m
Distance from central maxim of another wavelength = 0.39 m
We need to calculate the second wavelength
Using formula of width of fringe
Here, d and D will be same for both wavelengths
= wavelength
= width of fringe
The width of fringe for first wavelength
....(I)
The width of fringe for second wavelength
....(II)
Divided equation (I) by equation (II)
Hence, The second wavelength is 482 nm.