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3 years ago

Mars is 1.52 times as far from the Sun as Earth is. Predict the time required for Mars to orbit the Sun in Earth days.

Physics

1 answer:

Dafna11 [192]3 years ago

6 0

Answer:

Mars is 1.52 times as far from the Sun as Earth is. Predict the time required for Mars to orbit the Sun in Earth days.

Explanation:

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What is the moment of inertia of an object that rolls without slipping down a 3.5-m- high incline starting from rest, and has a

Daniel [21]

Answer:

I = 0.287 MR²

Explanation:

given,

height of the object = 3.5 m

initial velocity = 0 m/s

final velocity = 7.3 m/s

moment of inertia = ?

Using total conservation of mechanical energy

change in potential energy will be equal to change in KE (rotational) and KE(transnational)

PE = KE(transnational) + KE (rotational)

$mgh = \dfrac{1}{2}mv^2 + \dfrac{1}{2}I\omega^2$

v = r ω

$mgh = \dfrac{1}{2}mv^2 + \dfrac{1}{2}\dfrac{Iv^2}{r^2}$

$I = \dfrac{m(2gh - v^2)r^2}{v^2}$

$I = \dfrac{mr^2(2\times 9.8 \times 3.5 - 7.3^2)}{7.3^2}$

$I =mr^2(0.287)$

I = 0.287 MR²

3 0

3 years ago

Electromagnetic wav

krek1111 [17]

Answer:

I dont get what your asking sorry boo

Explanation:

6 0

2 years ago

Read 2 more answers

A rocket of mass 1000kg uses 5kg of fuel and oxygen to produce exhaust gases ejected at 500m/s calculate the increase its veloci

Vlad [161]

Answer:

Approximately $\rm 2.5\; m \cdot s^{-1}$ .

Explanation:

Let the increase in the rocket's velocity be $\Delta v$ . Let $v_0$ represent the initial velocity of the rocket. Note that for this question, the exact value of $v_0$ doesn't really matter.

The momentum of an object is equal to its mass times its velocity.

Mass of the rocket with the 5 kg of fuel: $1000$ .
Initial velocity of the rocket and the fuel: $v_0$ .
Hence the initial momentum of the rocket: $1000\,v_0$ .

Mass of the rocket without that 5 kg of fuel: $1000 - 5 = 995$ .
Final velocity of the rocket: $v_0 + \Delta v$ .
Hence the final momentum of the rocket: $995\,(v_0 + \Delta v)$ .

Mass of the 5 kg of fuel: $5$ .
Final velocity of the fuel: $v_0 - 500$ (assuming that the the 500 m/s in the question takes the rocket as its reference.)
Hence the final momentum of the fuel: $5\,(v_0 - 500)$ .

Momentum is conserved in an isolated system like the rocket and its fuel. That is:

Sum of initial momentum = Sum of final momentum.

$1000\,v_0 = 995\,(v_0 + \Delta v) + 5\,(v_0 - 500)$ .

Note that $1000\, v_0$ appears on both sides of the equation. These two terms could hence be eliminated.

$0 = 995\, \Delta v - 5\times 500$ .

$\displaystyle \Delta v = \frac{5}{995}\times 500 \approx \rm 2.5\; m \cdot s^{-1}$ .

Hence, the velocity of the rocket increased by around 2.5 m/s.

5 0

3 years ago

Please select the word from the list that best fits the definition

lina2011 [118]

Answer:

A subculture.

Explanation:

Aspects of a group that is based on the shared values and belief systems and the norms and behaviors aspects that are only a part of the subsection of society are called as subcultures. Like the goths, hippies, etc as its nor accepted by the entire population.

3 0

3 years ago

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A 2.0kg object is raised by a height of 0.5m.Calculate the energy raised in its gravitational potential energy store? G=9.8N/KG

notka56 [123]

Answer:

Gravitational potential energy stored is 9.8 J.

Given:

G = 9.8 $\frac{N}{kg}$

height = 0.5 m

mass = 2 kg

To find:

Gravitation Potential energy stored = ?

Formula used:

Potential energy = mGh

m = mass

G = acceleration due to gravity

h = height

Solution:

Potential energy of the object is given by,

Potential energy = mGh

m = mass

G = acceleration due to gravity

h = height

Potential energy = 2 × 9.8 × 0.5

Potential energy = 9.8 Joule

Gravitational potential energy stored is 9.8 J.

5 0

3 years ago