It's not possible to calculate the current with the given data. "Amp" is not a unit for measuring resistors, and "C" is not a unit for measuring batteries. So we don't know the resistance of this circuit or the potential difference applied to it, and thus can't calculate the current. If we could, it might turn out to be 3 gallons, but that's just a reckless guess.
Im sorry i looked it up and said you coldnt convert so.... : /
Option B The thickness of the central portion of a thin conveying lens can be determined very accurately by using a micrometer screw gauge.
<h3>What can be measured using a micrometer screw gauge?</h3>
One micrometer of thickness can be measured with a micron micrometre screw gauge. A Use of Micrometer Screw Gauge as like example Upon turning the screw of the micrometer screw gauge four times, a 2 mm space is covered.
<h3>What purposes does a micrometer serve?</h3>
A tool known as a micrometer is used to measure solid objects’ lengths, thicknesses, and other dimensions precisely and linearly.
<h3>What is the micrometer screw gauge’s SI unit?</h3>
The SI symbol m is also known as a micron, which is an SI-derived unit of length equaling 1106 meters, where 106 is the SI standard prefix for the prefix “micro-.” A micrometer is one-millionth of a meter.
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Answer:
y = [tg α] *x - [1/2 g/ (v0 ²cos²(α))]* x² , which describes a parabolic path
Explanation:
since
x = (v0 cos(α))t
where x represents horizontal distance covered by the projectile
and
y = (v0 sin(α))t −(1/2) gt^2
where y represents vertical distance, we can replace the parameter t in order to have a function of coordinates, then
x = (v0 cos(α))t → x /(v0 cos(α))= t
replacing t in the equation of y
y = (v0 sin(α))t −(1/2) gt^2 = (v0 sin(α))x/(v0 cos(α)) −(1/2) g[x/(v0 cos(α))]² =
[sin(α) /cos(α)]* x - 1/2 g x²/(v0 cos(α))² = [tg α] *x - [1/2 g/ (v0 ²cos²(α))]* x²
therefore
y = [tg α] *x - [1/2 g/ (v0 ²cos²(α))]* x²
since tg α= constant=C1 , [-1/2 g/ (v0 ²cos²(α))]= constant=C2 , then
y = C1*x + C2* x²
which describes a parabolic path
The correct answer to the question is - A). Light waves can travel in a vacuum and travel at a constant speed even if the light source is moving.
EXPLANATION:
Before going to answer this question, first we have to understand the fundamental postulate of quantum mechanics.
As per the fundamental postulate of quantum mechanics, the speed of light is always constant irrespective of the nature of frame of reference i.e speed of light is same both in inertial and non-inertial frame of reference. It is independent of the velocity of source also.
Again we know that light is an electromagnetic wave. Hence, it won't require any medium for its propagation. It can travel in space or vacuum also.
Hence, the correct option out of four options is that light waves can travel in a vacuum and travel at a constant speed even if the light source is moving.