Answer:
Pam: $181
Amanda: $362
Julie: $452
Step-by-step explanation:
(What does Mike have to do with this problem?)
Let a = Amanda's pay
Let p = Pam's pay
Let j = Julie's pay
"Amanda made twice what Pam earned"
a = 2p
"Julie made $90 more than Amanda"
j = a + 90
j = 2p + 90
Pam earned p
Total salary
a + p + j = 2p + p + 2p + 90
Total salary
$995
2p + p + 2p + 90 = 995
5p = 905
p = 181
a = 2p = 2(181) = 362
j = 2p + 90 = 362 + 90 = 452
Answer:
Pam: $181
Amanda: $362
Julie: $452
Answer:
The answer is R(2).
Step-by-step explanation:
hope this helped!
Given Information:
Population mean = p = 60% = 0.60
Population size = N = 7400
Sample size = n = 50
Required Information:
Sample mean = μ = ?
standard deviation = σ = ?
Answer:
Sample mean = μ = 0.60
standard deviation = σ = 0.069
Step-by-step explanation:
We know from the central limit theorem, the sampling distribution is approximately normal as long as the expected number of successes and failures are equal or greater than 10
np ≥ 10
50*0.60 ≥ 10
30 ≥ 10 (satisfied)
n(1 - p) ≥ 10
50(1 - 0.60) ≥ 10
50(0.40) ≥ 10
20 ≥ 10 (satisfied)
The mean of the sampling distribution will be same as population mean that is
Sample mean = p = μ = 0.60
The standard deviation for this sampling distribution is given by
Where p is the population mean that is proportion of female students and n is the sample size.
Therefore, the standard deviation of the sampling distribution is 0.069.
<em>X = 2 cm</em>
Volume = Bh= 8×5×1/2×X= 80
X = 80/20 = 4
The answer is:
It’s equivalent to 30+5y