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2 years ago

Suppose a triangle has 3,4, and 5 sides.Which of the following must be true

Mathematics

2 answers:

emmainna [20.7K]2 years ago

8 0

The answer would be C because you wouldn't know the angles yet.

Artyom0805 [142]2 years ago

5 0

Answer:

A. The triangle in question is a right triangle

Step-by-step explanation:

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(6,-3) and y = - 6x - 3

Hatshy [7]

Wait what's the question tho?
is it if this point is on the line?
cause it's not
-y=mx+b
3=-6(6)-3
-3=-36-3
-3 does not equal -39
hence, point is not on the line

3 0

2 years ago

A rectangle and a square have the same area. The length of the rectangle is seventy feet more than two times its width. The leng

Zanzabum

Using the side of the square find the area:

Area = 30^2 = 900 square feet.

The rectangles area is the same, 900 square feet.

Let the width = X

The length would be 2X + 70

Area = length x width

X * 2x+ 70 = 900

This expands to 2x^2 * 70x = 900

Use the quadratic formula to solve for x:

-70 +/- sqrt(70^2-4*2(-900))/2*2

X = 10

Width = x = 10 feet

Length = 2x + 70 = 90 feet

8 0

2 years ago

The probability of getting a head is 0.3 find the probability of getting a tail

ratelena [41]

Answer: 0.7

Step-by-step explanation:

p(tail) + p(head) = 1

p(tail) = 1 - p(head)

p(tail) = 1 -0.3

p(tail) = 0.7

mark the brainliest plzz

6 0

2 years ago

Write the sentence as an inequality.

kramer

2r + 6 > -24
........

7 0

2 years ago

Help pls im being timed

Nitella [24]

The trigonometric ratios show that the angle FHE is 48.59°.

<h3>RIGHT TRIANGLE</h3>

A triangle is classified as a right triangle when it presents one of your angles equal to 90º. The greatest side of a right triangle is called hypotenuse. And, the other two sides are called cathetus or legs.

The math tools applied for finding angles or sides in a right triangle are the trigonometric ratios or the Pythagorean Theorem.

The Pythagorean Theorem says: $(hypothenuse)^2=(leg_1)^2+(leg_2)^2$ . And the main trigonometric ratios are:

$sin(\alpha) =\frac{opposite \;leg }{hypotenuse} \\ \\ cos(\alpha) =\frac{adjacent\;leg }{hypotenuse} \\ \\ tan(\alpha) =\frac{sin(\alpha )}{cos(\alpha )}= \frac{opposite \;leg }{adjacent\;leg } \\ \\$

It is important to remember that the sum of internal angles for any triangle is 180°.

From the question, it is possible to see 2 right triangles (HGF and FHE).

You can find the hypotenuse of the triangle HGF from the trigonometric ratio: sen Θ

$sin45=\frac{opposite\; leg }{hypotenuse} =\frac{\sqrt8}{hypotenuse}\\ \\ \frac{\sqrt{2} }{2} =\frac{\sqrt{8} }{hypotenuse} \\ \\ \sqrt{2}*hypotenuse=2\sqrt{8} \\ \\ hypotenuse=\frac{2\sqrt{8} }{\sqrt{2}} =2\sqrt{4} =2*2=4$

The hypotenuse of triangle HGF is one of legs for the triangle FHE. The, you can find the angle FHE from the trigonometric ratio: tan β. Thus,

$sin \beta =\frac{opposite\; leg }{adjacent\; leg} =\frac{3}{4}\\ \\ sin \beta=\frac{3}{4}=0.84806\\ \\ arcsin\beta =48.59^{\circ \:}$

Learn more about trigonometric ratios here:

brainly.com/question/11967894

#SPJ1

7 0

1 year ago