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Pie
3 years ago
15

Assuming the ball's initial velocity was 57° above the horizontal and ignoring air resistance, what did the initial speed of the

ball need to be to produce such a home run if the ball was hit at a point 0.9 m (3.0 ft) above ground level?
Assume that the ground was perfectly flat. Express your answer using two significant figures. v₀ = ______ m/s
How far would the ball be above a fence 3.0 m (10 ft) high if the fence was 116 m (380 ft) from home plate? Express your answer using two significant figures. h = _______ m

Physics
1 answer:
UNO [17]3 years ago
7 0

Answer:

V0 = 44.97m/s

Height above fence = 66.67m

Explanation:

The detailed calculation is done as shown in the attachment

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Suppose we hang a heavy ball with a mass 13 kg (so the weight is ) from a steel wire 3.9 m long that is 3.1 mm in diameter (radi
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1.635×10^-3m

Explanation:

Young modulus is the ratio of the tensile stress of a material to its tensile strain.

Young modulus = Tensile stress/tensile strain

Tensile stress = Force/Area

Given force = 130N

Area = Πr² = Π×(1.55×10^-3)²

Area = 4.87×10^-6m²

Tensile stress = 130/4.87×10^-6 = 8.39×10^7N/m²

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Tensile strain = e/3.9

Substituting in the young modulus formula given young modulus to be 2×10¹¹N/m²

2×10¹¹N/m² = 8.39×10^7/{e/3.9)}

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1.635×10^-3m

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