This Question has mistakes.Correct question is
An undamped oscillator has period τo=1.000s
, but I now add a little damping so that its period changes to τ1=1.001s.
What is the damping factor β? By what factor will the amplitude of oscillation decrease after 10 cycles? Which effect of damping would be more noticeable, the change of period or the decrease of the amplitude?
Answer:
β=0.28 /sec
Amplitude=0.0606
Explanation:
A) 1.05 N
The power dissipated in the circuit can be written as the product between the pulling force and the speed of the wire:
where
P = 4.20 W is the power
F is the magnitude of the pulling force
v = 4.0 m/s is the speed of the wire
Solving the equation for F, we find
B) 3.03 T
The electromotive force induced in the circuit is:
(1)
where
B is the strength of the magnetic field
v = 4.0 m/s is the speed of the wire
L = 10.0 cm = 0.10 m is the length of the wire
We also know that the power dissipated is
(2)
where
is the resistance of the wire
Subsituting (1) into (2), we get
And solving it for B, we find the strength of the magnetic field:
Answer:
10 m
Explanation:
Weight = 10 N
mg = 10
m = 10 / 10 = 1 kg
g = 10 m/s^2
Initial mechanical energy = 40 J
Final mechanical energy = 140 J
change in total energy = 140 J – 40 J = 100 J
At the maximum vertical height, the velocity = 0 m/s
So,it has only potential energy at maximum height
P = m x g x h
100 = 1 x 10 x h
h = 10 m
Answer:
C
Explanation:
Gravity will always be attractive because it pulls things not push. For example gravity pull people to earth, that is why we don't float.