Assuming the ball's initial velocity was 57° above the horizontal and ignoring air resistance, what did the initial speed of the
ball need to be to produce such a home run if the ball was hit at a point 0.9 m (3.0 ft) above ground level?
Assume that the ground was perfectly flat. Express your answer using two significant figures. v₀ = ______ m/s
How far would the ball be above a fence 3.0 m (10 ft) high if the fence was 116 m (380 ft) from home plate? Express your answer using two significant figures. h = _______ m
Assume that the ground was perfectly flat. Express your answer using two significant figures. v₀ = ______ m/s
How far would the ball be above a fence 3.0 m (10 ft) high if the fence was 116 m (380 ft) from home plate? Express your answer using two significant figures. h = _______ m
1 answer:
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Answer:
v = 10 m/s
Explanation:
Given,
Length of the vine, l = 36 m
Angle of inclination = 31.0◦ with the vertical
acceleration due to gravity = 9.81 m/s²
Using Conservation of energy
KE = PE
v = 10 m/s
Hence, the speed of the swing is equal to 10 m/s
Answer:
I2>I1
Explanation:
This problem can be solved by using the parallel axis theorem. If the axis of rotation of a rigid body (with moment of inertia I1 at its center of mass) is changed, then, the new moment of inertia is gven by:
where M is the mass of the object and d is the distance of the new axis to the axis of the center of mass.
It is clear that I2 is greater than I1 by the contribution of the term Md^2.
I2>I1
hope this helps!!