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sladkih [1.3K]
2 years ago
10

An object experiencing uniform circular motion is accelerating. t/f

Physics
1 answer:
tigry1 [53]2 years ago
8 0

Answer:

According to Newton's second law of motion, a net force causes the acceleration of mass according to Fnet = ma. For uniform circular motion, the acceleration is centripetal acceleration: a = ac. Therefore, the magnitude of centripetal force, Fc, is F c = m a c F c = m a c .

Explanation:

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What is the force on an object that accelerates at 2 m/s/s and has a mass of 120 kg
11111nata11111 [884]

Answer:

240 Newtons

Explanatiohn:

f = m × a

f = 120 × 2

f = 240 Newtons

<h3>The force is 240 Newtons</h3>
6 0
3 years ago
Parasaurolophus was a dinosaur whose distinguishing feature was a hollow crest on the head. The 1.5-m-long hollow tube in the cr
Oksi-84 [34.3K]

Answer:

f1 = 58.3Hz, f2 = 175Hz, f3 = 291.6Hz

Explanation:

lets assume speed of sound is 350 m/s.

frequencies of a standing wave modes of an open-close tube of length L

fm = m(v/4L)

where m is 1,3,5,7......

and fm = mf1

where f1 = fundamental frequency

so therefore: f1 = 350 x 4 / 1.5

f1 = 58.3Hz

f2 = 3 x 58.3

f2 = 175Hz

f3 = 5 x 58.3

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5 0
3 years ago
In the absence of air resistance, at what other angle will a thrown ball go the same distance as one thrown at an angle of 75 de
snow_tiger [21]

As we know that range of the projectile motion is given by

R = \frac{v^2 sin(2\theta)}{g}

here we know that range will be same for two different angles

so here we can say the two angle must be complementary angles

so the two angles must be

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so it is given that one of the projection angle is 75 degree

so other angle for same range must be 90 - 75 = 15 degree

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5 0
3 years ago
The graph above shows the position and time calculate the velocity of the particle from T=0s to T=4s?
zzz [600]

Answer:

The velocity of the particle from T = 0 s to T = 4 s is;

0.5 m/s

Explanation:

The given parameters from the graph are;

The initial displacement (covered) at time, t₁ = 0 s is x₁ = 1 m

The displacement covered at time, t₂ = 4 s is x₂ = 3 m

The graph of distance to time, from time t = 0 to time t = 4 is a straight line graph, with the velocity given by the rate of change of the displacement to the time which is dx/dt which is also the slope of the graph given as follows;

The \ slope \ of \ the \ displacement \ time \ graph, \ m =velocity, \ v= \dfrac{x_2 - x_1}{t_2 - t_1}

Therefore, \ the \ velocity \ of \ the \ particle \ v  = \dfrac{3 \  m - 1 \ m}{4 \ s - 0 \ s}  = \dfrac{2 \ m}{4 \  s} = \dfrac{1}{2} \ m/s

The velocity of the particle from t = 0 s to t  = 4 s = 1/2 m/s = 0.5 m/s.

3 0
2 years ago
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