The equator would be warmer than the poles. :)
Answer:
honest-humility
Explanation:
The Big Five model for personality is a model in psychology that aimed to evaluate the personality of the people with five big treats that could describe the general personality of their persona, most of the critics of that model critized it believed that it was lacking another trait which was Honest-Humility, and how that is involved in the development of the personality of a person.
Answer:
Momentum (P)= 3.15Kg.m/s
Explanation:
Because momentum by definition is the product of mass and velocity, therefore, it's calculated by the formula;
P=mv,,,
where 'P' Is the momentum
'm' is mass in Kilograms, note that mass should be in Kilograms, therefore the 450grams should be converted to kilograms by dividing it with a 1000, i.e (450g×1kg/1000g)= 0.45kg, and now you can substitute in the formula because you have everything you need to find momentum in the right si units.
so P=mv
P=0.45Kg×7m/s
P=3.15Kg.m/s
Answer:
l3/l = 2
Explanation:
Suppose B1 is the magnetic field due to cable 1 and B2 is the field due to cable 2. Therefore, the magnitude of the field at a distance from the cable is equal to:
B = (uo*I)/(2*pi*r)
B1-2 = (B1^2 + B2^2)^1/2 = ((((uo*I)/(2*pi*r)^2 + (uo*I)/(2*pi*r)^2))))))^1/2 = (2^1/2)*(uo*l)/(2*pi*r)
From this equation we can say that the direction of the field will be from the corner that is empty and cable 3:
B3 = B1-2
(uo*l3)/(2*pi*(2^1/2)*r = (2^1/2)*(uo*l)/(2*pi*r)
From here we have that the relationship between both currents will be equal to:
l3/l = 2
Answer:
a) Δx₂ = 31*Δt
b) Δx₁ = 977.5 / a
c) a = 23 / Δt
e) Δx₁ = 42.5*Δt
g) Δt = 0.0565 h
i) a = 0.05 m/s²
Explanation:
Given
v₁ = 54 Mi/h
v₂ = 31 Mi/h
a) We apply the formula
Δx₂ = v₂*Δt
⇒ Δx₂ = 31*Δt (Assuming constant speed)
b) We use the formula
v₂² = v₁² - 2*a*Δx₁ ⇒ Δx₁ = (v₁² - v₂²) / (2*a)
⇒ Δx₁ = (54² - 31²) / (2*a)
⇒ Δx₁ = 977.5 / a
c) We use the equation
v₂ = v₁ - a*Δt ⇒ a = (v₁ - v₂) / Δt
⇒ a = (54 - 31) / Δt
⇒ a = 23 / Δt
e) We apply the formula
Δx₁ = v₁*Δt - 0.5*a*Δt²
Δx₁ = 54*Δt - 0.5*(23 / Δt)*Δt²
⇒ Δx₁ = 42.5*Δt
g) If Δx₁ = 2.4 Mi ⇒ 2.4 = 42.5*Δt ⇒ Δt = 0.0565 h
i) If a = 23 / Δt ⇒ a = 23 Mi / 0.0565 h = 407.29 Mi/h²
⇒ a = 0.05 m/s²
