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ryzh [129]
3 years ago
12

First extinguish a match or candle by blasting it violently. Why?​

Physics
1 answer:
Andreas93 [3]3 years ago
7 0

Answer:

The wax vapor on burning candles could reignite the flame.

Explanation:

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Biologists use optical tweezers to manipulate micron-sized objects using a beam of light. In this technique, a laser beam is foc
vekshin1

Answer:

Explanation:

Part A) Using

light intensity I= P/A

A= Area= π (Radius)^2= π((0.67*10^-6m)/(2))^2= 1.12*10^-13 m^2

Radius= Diameter/2

P= power= 10*10^-3=0.01 W

light intensity I= 0.01/(1.12*10^-13)= 9*10^10 W/m^2

Part B)  Using

I=c*ε*E^2/2

rearrange to solve for E= \sqrt{((I*2)/(c*ε))

c is the speed of light which is 3*10^8 m/s^2

ε=permittivity of free space or dielectric constant= 8.85* 10^-12 F⋅m−1

I= the already solved light intensity= 8.85*10^10 W/m^2

amplitude of the electric field E= \sqrt{(9*10^10 W/m^2)*(2) / (3*10^8 m/s^2)*(8.85* 10^-12 F⋅m−1)

---> E= \sqrt{(1.8*10^11) / (2.66*10^-3) = \sqrt{(6.8*10^13) = 8.25*10^6 V/m    

 

8 0
3 years ago
What is the heat extracted from the cold reservoir for the refrigerator?
zaharov [31]
What is the heat extracted from the cold reservoir for the refrigerator shown in(Figure 1) ? Assume that W1 = -123J and W2 = 88J . 

<span>Qc= _________ </span>

<span>Part B 
</span>
K=105J
7 0
3 years ago
An electron drops from the n=6 to the n=4 level of an infinite square well that is 3.10-11 m wide. What is the wavelength of the
almond37 [142]
The answer would be C !
4 0
3 years ago
Please help i don't understand. will mark brainliest
soldier1979 [14.2K]

Answer:

marblebrainiest plz\c cmarble

Explanation:

8 0
3 years ago
Read 2 more answers
A fairground ride consists of a large vertical drum that spins so
expeople1 [14]

Answer:

v = 3.84 m/s

Explanation:

In order for the riders to stay pinned against the inside of the drum the frictional force on them must be equal to the centripetal force:

Centripetal\ Force = Frictional\ Force\\\\\frac{mv^2}{r} = \mu R = \mu W\\\\\frac{mv^2}{r} = \mu mg\\\\\frac{v^2}{r} = \mu g\\\\v = \sqrt{\mu gr}

where,

v = minimum speed = ?

g = acceleration due to gravity = 9.81 m/s²

r = radius = 10 m

μ = coefficient of friction = 0.15

Therefore,

v=\sqrt{(0.15)(9.81\ m/s^2)(10\ m)}

<u>v = 3.84 m/s</u>

6 0
3 years ago
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