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3 years ago

6

Using -10 m/s2 for acceleration due to gravity, what would be the total displacement of the object if it took 8 seconds before h

itting the water?

1 answer:

ASHA 777 [7]3 years ago

6 0

If it starts from 0m/s...
s=?
u=0
a=-10
t=8
s=ut +1/2at^2
so s=(0×8)+ (0.5×-10×64)
s=0+(32×-10)
s=32×-10
s=-320metres

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Coherent light of frequency 6.37×1014 Hz passes through two thin slits and falls on a screen 88.0 cm away. You observe that the

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Answer:

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Given that,

Frequency $f= 6.37\times10^{14}\ Hz$

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Using formula of wavelength

$\lambda=\dfrac{c}{f}$

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Put the value into the formula

$\lambda=\dfrac{3\times10^{8}}{6.37\times10^{14}}$

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We need to calculate the distance between the two slits

$m\times \lambda=d\sin\theta$

$d =\dfrac{m\times\lambda}{\sin\theta}$

Where, m = number of fringe

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Here, $\sin\theta =\dfrac{y}{l}$

Put the value into the formula

$d=\dfrac{3\times471\times10^{-9}\times88.0\times10^{-2}}{3.10\times10^{-2}}$

$d=40.11\times10^{-6}\ m$

$d = 40.11\ \mu m$

Hence, The distance between the two slits is 40.11 μm.

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