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2 years ago

What is the potential difference needed to achieve a current of 16A with a resistance of

Physics

1 answer:

Fiesta28 [93]2 years ago

6 0

Hi there!

We can use the following equation:
$\large\boxed{V = I R}$

V = potential difference (? V)
I = Current (16A)
R = Resistance (192Ω)

Plug in the givens and solve:

$F = 16 \times 192 = \boxed{3072 V}$

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Three basic classes of collisions include all but which of the following?

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8. How did the measured angular magnification of the telescope compare with the theoretical prediction?

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Complete Question

The complete question is shown on the first uploaded image

Answer:

The theoretical angular magnification lies within the angular magnification range

Explanation:

From the question we are told that

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The focal length of A is $f_{eye} = 10.4 \ cm$

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3 years ago

Santa doesn't want to push a 25.0 kg wooden box across a wooden floor with a uk of 0.20 at

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Answer:

49 N

Explanation:

In order to move the box at constant speed, the acceleration of the box must be zero (a=0): this means, according to Newton's second law,

F = ma

that the net force acting on the box, F, must be zero as well.

Here there are two forces acting on the box in the horizontal direction while it is moving:

- The force of push applied by the guy, F

- The frictional force, $F_f$

For an object moving on a flat surface, the frictional force is given by

$F_f = \mu_k mg$

where

$\mu_k$ is the coefficient of friction

m is the mass of the box

g is the acceleration of gravity

So the equation of the forces becomes

$F-\mu_k mg = 0$

And substituting:

$\mu_k = 0.20\\m = 25.0 kg\\g = 9.8 m/s^2$

We find the force that must be applied by the guy:

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3 years ago

bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving +1.72 m/s what is the veloci

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Answer: V1 = 3.559 - 0.744V2

Explanation: Given that the

bumper car A has

Mass M1 = (281 kg) moving with

Velocity U1 = 2.82 m/s

bumper car B has

Mass M2 = (209 kg) moving with

Velocity U2 = 1.72 m/s

Where U1, U2 are the initial velocity of the two cars

Since the collision is elastic, we will use the formula below,

M1U1 + M2U2 = M1V1 + M2V2

Substitute the values into the formula

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Therefore, the velocity of car A which

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3 years ago