Answer:
(a) 388 newton
(b) 17.15 m/s
Explanation:
r = 30 m
v = 10 m/s
m = 60 kg
(a) Let N be the normal reaction.
At the bump
N = mg - mv^2 / r
N = 60 x 9.8 - 60 x 10 x 10 / 30 = 588 - 200 = 388 newton
(b) Then the contact loose, N = 0
So, mg = mv^2 / r
v^2 = r x g = 30 x 9.8 = 294
v = 17.15 m/s
Answer:
1500kg
Explanation:
Assuming that the women push the car in the same direction, then the total force is:
Fnet = 425 N ⋅ 3
= 1275 N
To find the mass, we use Newton's second law of motion, which states that,
F = ma
where:
·F is the force applied in newtons
·m is the mass of the object in kilograms
·a is the acceleration of the object in meters per second squared.
So we get:
F
m= ⁻⁻⁻⁻⁻
a
1275N
= ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
0.85 m/s²
= 1500 kg
The voltage provided by the power supply = 20 V
<h3>Resistors in series </h3>
The Voltage across resistors in series in a circuit is equal to the sum of the voltage drops across each resistor.
Therefore for two resistors in series the total voltage provided by the power supply is equivalent to the summation of the voltage drops acroos each resistor ( i.e 10 V + 10 V = 20 V )
Hence we can conclude that the voltage provided by the power supply is 20 V
Learn more about reisitors in series : brainly.com/question/11657573
Answer:
It is commonly known that, if you accelerate an object, its mass will increase; however, to understand why this phenomenon occurs, we mustn’t think of the object’s mass increasing. Instead, we should think of its energy. In physics, mass is just simply locked up energy. We call this type of mass, ‘inertial mass.’
Answer:
b) Springs oscillate with the same frequency,
Explanation:
expression for frequency of vibration of mass hanging from a spring is given as follows
f =
k is force constant of spring and m is mass vibrating .
In the present case, if mass stretches the spring by x and remains balanced
mg = k x
g and x are same for both cases
will also be same for both cases .
Hence frequency of vibration will also be same for both the balls .