Question

On the moon the surface temperature ranges from 379 K during the day to 1.04 x 102 K at night. Convert these temperatures to the Celsius and Fahrenheit scales.
(a) 379 K in degrees Celsius;
(b) 379 K in degrees Fahrenheit;
(c) 1.04 x 102 K in degrees Celsius;
(d) 1.04 x 102 K in degrees Fahrenheit.

Answer 1

Answer:

Explanation:

Relation between Celsius and Kelvin is

K = C + 273

Relation between Kelvin and Fahrenheit is

$\frac{K-273}{100}=\frac{F -32}{180}$

(a) 379 K

Relation between Celsius and Kelvin is

K = C + 273

So, C = K - 273 = 379 - 273 = 106

Thus, 379 K = 106°C.

(b) 379 K

Relation between Kelvin and Fahrenheit is

$\frac{K-273}{100}=\frac{F -32}{180}$

$\frac{379-273}{100}=\frac{F -32}{180}$

F = 222.8°F

Thus, 379 K = 222.8°F

(c) 1.04 x 10^2 K = 104 K

Relation between Celsius and Kelvin is

K = C + 273

So, C = K - 273 = 104 - 273 = -169

Thus, 104 K = - 169°C.

(d) 1.04 x 10^2 K = 104 K

Relation between Kelvin and Fahrenheit is

$\frac{K-273}{100}=\frac{F -32}{180}$

$\frac{104-273}{100}=\frac{F -32}{180}$

F =- 272.2°F

Thus, 104 K = - 272.2°F