Two children push on heavy crate that rests on a basement floor. one pushes horizontally with a force of 150 N and the other pus
1 answer:
The force of friction is 330 N
Explanation:
We can solve this problem by applying Newton's second law of motion, which states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:
where
is the net force
m is the mass
a is the acceleration
For the crate in this problem, we have 3 forces acting on it:
- The force applied by the 1st child, forward
- The force applied by the 2nd child,
- The force of friction, , acting backward
So the net force is
We also know that the crate remains stationary, which means that its acceleration is zero:
a = 0
Therefore, we can rewrite Newton's second law as
From which we find
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A) The mass is an intrinsic property of an object: it means it depends only on the properties of the object, so it does not depend on the location of the object. Therefore, Gary's mass at 300 km above Earth's surface is equal to his mass at the Earth's surface.
b) The weight of an object is given by
where
m is the mass
is the gravitational acceleration at the location of the object, with G being the gravitational constant, M the mass of the planet and r the distance of the object from the center of the planet.
At the Earth's surface,
, so Gary's weight is
(1)
where m is Gary's mass.
Then, we must calculate the value of g at 300 km above Earth's surface. the Earth's radius is
So the distance of Gary from the Earth's center is
The Earth's mass is
, so the gravitational acceleration is
Therefore, Gary's weight at 300 km above Earth's surface is
(2)
If we compare (1) and (2), we find that Gary's weight has changed by
So, Gary's weight at 300 km above Earth's surface is 91% of his weight at the surface.
b) The weight of an object is given by
where
m is the mass
At the Earth's surface,
where m is Gary's mass.
Then, we must calculate the value of g at 300 km above Earth's surface. the Earth's radius is
So the distance of Gary from the Earth's center is
The Earth's mass is
Therefore, Gary's weight at 300 km above Earth's surface is
If we compare (1) and (2), we find that Gary's weight has changed by
So, Gary's weight at 300 km above Earth's surface is 91% of his weight at the surface.