Two children push on heavy crate that rests on a basement floor. one pushes horizontally with a force of 150 N and the other pus
1 answer:
The force of friction is 330 N
Explanation:
We can solve this problem by applying Newton's second law of motion, which states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:
where
is the net force
m is the mass
a is the acceleration
For the crate in this problem, we have 3 forces acting on it:
- The force applied by the 1st child, forward
- The force applied by the 2nd child,
- The force of friction, , acting backward
So the net force is
We also know that the crate remains stationary, which means that its acceleration is zero:
a = 0
Therefore, we can rewrite Newton's second law as
From which we find
Learn more about friction and Newton's second law:
#LearnwithBrainly
You might be interested in
Answer:
d = 68.5 x 10⁻⁶ m = 68.5 μm
Explanation:
The complete question is as follows:
An optical engineer needs to ensure that the bright fringes from a double-slit are 15.7 mm apart on a detector that is 1.70m from the slits. If the slits are illuminated with coherent light of wavelength 633 nm, how far apart should the slits be?
The answer can be given by using the formula derived from Young's Double Slit Experiment:
where,
d = slit separation = ?
λ = wavelength = 633 nm = 6.33 x 10⁻⁷ m
L = distance from screen (detector) = 1.7 m
y = distance between bright fringes = 15.7 mm = 0.0157 m
Therefore,
<u>d = 68.5 x 10⁻⁶ m = 68.5 μm</u>
Answer:
The intensity of sound (I) = 3.16 x 10⁻⁶ W/m²
Explanation:
We have expression for sound intensity level (SIL),
Here we need to find the intensity of sound (I).
Substituting
L = 67 dB and I₀ = 10⁻¹² W/m² in the equation
The intensity of sound (I) = 3.16 x 10⁻⁶ W/m²