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blagie [28]
3 years ago
9

Two children push on heavy crate that rests on a basement floor. one pushes horizontally with a force of 150 N and the other pus

hes in the same direction with a force of 180 N. The crate remains stationary. Show that the force of friction between the crate the floor is 330 N.
Physics
1 answer:
Makovka662 [10]3 years ago
3 0

The force of friction is 330 N

Explanation:

We can solve this problem by applying Newton's second law of motion, which states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:

sum F = ma

where

\sum F is the net force

m is the mass

a is the acceleration

For the crate in this problem, we have 3 forces acting on it:

- The force applied by the 1st child, F_1 = 150 N forward

- The force applied by the 2nd child, F_2 = 180 N

- The force of friction, F_f, acting backward

So the net  force is

\sum F = F_1 + F_2 - F_f

We also know that the crate remains stationary, which means that its acceleration is zero:

a = 0

Therefore, we can rewrite Newton's second law as

F_1 + F_2 - F_f = 0

From which we find

F_f = F_1+F_2 = 150 + 180 =330 N

Learn more about friction and Newton's second law:

brainly.com/question/6217246

brainly.com/question/5884009

brainly.com/question/3017271

brainly.com/question/2235246

brainly.com/question/3820012

#LearnwithBrainly

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Answer:

The work done on the suitcase is, W = 1691 J

Explanation:

Given data,

The force on the suitcase is, F  = 89 N

The distance Russell dragged the suitcase, S = 19 m

The work done on the suitcase by Russell is equal to the work done on the suitcase to overcome the friction

The work done on the suitcase by Russell is given by the formula

                          W = F · S

Substituting the given values,

                           W = 89 N x 19 m

                           W = 1691 J

Hence, the work done on the suitcase is, W = 1691 J

8 0
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A skydiver has a mass of 65 kg.<br> Calculate the weight of the skydiver.
Vinil7 [7]
F=m*a
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3 0
3 years ago
MATHPHYS HELP
rusak2 [61]

Answer:

16.4287

Explanation:

The force and displacement are related by Hooke's law:

F = kΔx

The period of oscillation of a spring/mass system is:

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First, find the value of k:

F = kΔx

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k = 0.796 N/m

Next, find the mass of the unknown weight.

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Finally, find the period.

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T = 2π√(5.44 kg / 0.796 N/m)

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Answer:

453 gm

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