Question

A beetle crawls from x=1.09m to x=2.55m in 12.8s. what was the average velocity?

Answer 1

The average velocity of the beetle is equal to the ratio between the displacement and the time:

$v=\frac{S}{t}$

The displacement of the beetle is

$S=2.55 m-1.09 m=1.46 m$

The time is t=12.8 s

Therefore, the average velocity is

$v=\frac{S}{t}=\frac{1.46 m}{12.8 s}=0.11 m/s$

in the positive x-direction.