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3 years ago

State one way of reducing the risks to a doctor who uses gamma radiation.

Physics

2 answers:

Reptile [31]3 years ago

6 0

Answer:

Some examples are:

Reducing the work hours of the doctor (at least in that area): Being exposed less time to the radiation will decrease the total dose that the doctor receives in a day, reducing the risks in a big factor.

Work at distance, in a shielded place: Working far away from the machine and in a shielded place (walls with lead for example) will reduce the total radiation that reaches the doctor, so at the end of the day, the total dose will be greatly decreased.

NNADVOKAT [17]3 years ago

4 0

Wearing protective gear such as a lead shield

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A thin spherical shell has a radius of 0.70 m. An applied torque of 860 N m gives the shell an angular acceleration of 4.70 rad/

Artyom0805 [142]

Answer:

$I=182.97\ kg-m^2$

Explanation:

Given that,

Radius of a spherical shell, r = 0.7 m

Torque acting on the shell, $\tau=860\ N$

Angular acceleration of the shell, $\alpha =4.7\ m/s^2$

We need to find the rotational inertia of the shell about the axis of rotation. The relation between the torque and the angular acceleration is given by :

$\tau=I\alpha$

I is the rotational inertia of the shell

$I=\dfrac{\tau}{\alpha }\\\\I=\dfrac{860}{4.7}\\\\I=182.97\ kg-m^2$

So, the rotational inertia of the shell is $182.97\ kg-m^2$ .

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Is it true or false that air pollution only occurs as a result of human activity

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In a closed system, a cart with a mass of 1.5 kg is rolling to the right at 1.4 m/s, while another cart of mass 1.0 kg is rollin

bija089 [108]

Answer: The correct option is (c.).

Explanation:

Mass of the cart A= 1.5 kg

Velocity of Cart A = 1.4 m/s towards right

Mass of the cart B = 1.0 kg

Velocity of Cart B = 1.4 m/s towards left

Momentum (P)= Mass × Velocity

$P_A=1.5 kg\times 1.4 m/s=2.1 kg m/s$

$P_B=1.0 kg\times (-1.4m/s)=-1.4 kg m/s$

(Negative sign means velocity of the cart is in opposite direction of that of the cart A)

Total Momentum = $P_A+P_B=2.10 kg m/s-1.40 kg m/s=0.70 kg m/s$

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The equivalent resistance of n resistors in series is given by:
$R_{eq} = R_1 + R_2 + ... + R_n$
In our circuit, we have three resistors of $10.0 \Omega$ each, therefore the equivalent resistance of the circuit is
$R_{eq} = R_1 + R_2 + R_3 = 10.0 \Omega + 10.0 \Omega + 10.0 \Omega =30.0 \Omega$

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Answer:In a series circuit, adding more resistors increases total resistance and thus lowers current. But the opposite is true in a parallel circuit because adding more resistors in parallel creates more choices and lowers total resistance. If the same battery is connected to the resistors, current will increase.

Explanation:

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