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2 years ago

State one way of reducing the risks to a doctor who uses gamma radiation.

Physics

2 answers:

Reptile [31]2 years ago

6 0

Answer:

Some examples are:

Reducing the work hours of the doctor (at least in that area): Being exposed less time to the radiation will decrease the total dose that the doctor receives in a day, reducing the risks in a big factor.

Work at distance, in a shielded place: Working far away from the machine and in a shielded place (walls with lead for example) will reduce the total radiation that reaches the doctor, so at the end of the day, the total dose will be greatly decreased.

NNADVOKAT [17]2 years ago

4 0

Wearing protective gear such as a lead shield

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2 years ago

A person travels by car from one city to another with differem constan1 speeds between pairs of cities. She drives for 30.0 min

Montano1993 [528]

Answer:

a.52.9 km/h

b.90 km

Explanation:

We are given that

$v_1=89km/h$

$t_1=30min$

$v_2=100km/h$

$t_2=12min$

$v_3=40km/h$

$t_3=45 min$

Time spend on eating lunch and buying ga=15 min.

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1 hour=60 minutes

Distance= $speed\times time$

$d_1=v_1\times t_1=80\times\frac{30}{60}=40km$

$d_2=100\times \frac{12}{60}=20 km$

$d_3=40\times \frac{45}{60}=30 km$

Total distance= $d_1+d_2+d_3=40+20+30=90km$

Average speed= $\frac{total\;speed}{total\;time}$

Using the formula

Average speed= $\frac{90}{1.7}=52.9Km/h$

b.Total distance between the initial and final city lies along the route=90 km

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Answer:

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