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2 years ago

State one way of reducing the risks to a doctor who uses gamma radiation.

Physics

2 answers:

Reptile [31]2 years ago

6 0

Answer:

Some examples are:

Reducing the work hours of the doctor (at least in that area): Being exposed less time to the radiation will decrease the total dose that the doctor receives in a day, reducing the risks in a big factor.

Work at distance, in a shielded place: Working far away from the machine and in a shielded place (walls with lead for example) will reduce the total radiation that reaches the doctor, so at the end of the day, the total dose will be greatly decreased.

NNADVOKAT [17]2 years ago

4 0

Wearing protective gear such as a lead shield

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The amount of heat needed to increase the temperature of a substance by $\Delta T$ is given by
$Q= mC_s \Delta T$
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If we re-arrange the formula, we get
$C_s = \frac{Q}{m \Delta T}$
And if we plug the data of the problem into the equation, we can find the specific heat capacity of the substance:
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3 years ago

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vodomira [7]

Answer:

F = 12.5N

Explanation:

Force (F) = Mass (m) x Acceleration (a)

F = ma

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3 years ago

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wlad13 [49]

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Bare free charges do not remain stationary when close together. To illustrate this, calculate the acceleration of two isolated p

Marta_Voda [28]

Answer:

Acceleration, $a=9.91\times 10^{15}\ m/s^2$

Explanation:

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Separation between the protons, $r=3.73\ nm=3.73\times 10^{-9}\ m$

Charge on protons, $q=1.6\times 10^{-19}\ C$

Mass of protons, $m=1.67\times 10^{-27}\ kg$

We need to find the acceleration of two isolated protons. It can be calculated by equating electric force between protons and force due to motion as :

$ma=\dfrac{kq^2}{r^2}$