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Yakvenalex [24]

2 years ago

9

In a typical badminton swing the racket is in contact with the birdy for about 0.0010 seconds. If the 0.045kg birdy acquires a s

peed of 67 m/s, what is the force exerted by the racket on the ball

1 answer:

zepelin [54]2 years ago

3 0

Answer:

3015 N

Explanation:

From Newton's second law, we know that;

F.t = mv

F = force on the ball= ?

m= mass of the ball

v= velocity

F= mv/t

F= 0.045 × 67/0.0010

F= 3.015/0.0010

F= 3015 N

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