Answer:
The ratio of the young's modulus of steel and copper is 
(c) is correct option.
Explanation:
Given that,
Length of steel wire = 4.7 m
Cross section
Length of copper wire = 3.5 m
Cross section
We need to calculate the ratio of young's modulus of steel and copper
Using formula of young's modulus for steel wire
....(I)
The young's modulus for copper wire
....(II)
From equation (I) and (II)
The ratio of the young's modulus of steel and copper
Hence, The ratio of the young's modulus of steel and copper is
Answer : B. 0 m/s∧2
Now we know that velocity = distance/ time
And acceleration = velocity/time.
From the graph we see that at the time interval 2 secs,the distance travelled is 10 m. Hence the velocity(v1) =10/2 = 5m/s.
From the graph we see that at the time interval 5 secs,the distance travelled is 25 m. Hence the velocity (v2) =25/5 = 5m/s.
Now acceleceration between the time interval of 2 ad 5 secs is calculated as
(v1-v2)/t2-t1 = (5-5)/(5-2) = 0 m/s∧2
Answer:
Mars2 illuminated side of the planet is very heat, dark side very cool
Venus 2 a warm planet with a constant temperature across the entire surface
Explanation:
For this hypothetical case, when changing the planets they are changed with their current characteristics.
Case of Mars2
In this case, there is a planet with a very thin atmosphere, so the solar radiation reaches the ground without damping it, causing a lot of noise, so the illuminated side of the planet is very heat and when the dark side turns due to the little atmosphere it loses everything the heat for which it is very cold.
This thermal stress between the two sides of the planet continues constantly creating possible fruit trees in its rocky systems.
Case of Venus 2
The planet has a high atmospheric density, but it is very far from the sun, so the amount of radiation that arrives slightly warms the planet, but due to the thin atmosphere the losses for the dark period are very small, so the entire planet it is heated until it reaches an almost uniform temperature over its entire surface.
In this case we have a warm planet with a constant temperature across the entire surface, regardless of which side is lit.
Answer:
Suck up the iron using the electromagnet.
Explanation:
Iron is magnetic and copper is not. So copper will be
unaffected by the magnet. After extracting the iron,
open the switch. The electromagnet will lose its
magnetism and the iron fillings will fall off..
Here, you can derive that by numerical method, as follows:
F = m.a
m = F/a
So, here we can see when we decrease one, other increase by same effect; we can say they are "Indirectly Proportional" to each other!
Hope this helps!
