When a ball is whirled using a string, it is restricted to move only in circular motion because the net force acting on the ball is towards the center of the circle. Hence, the acceleration of the ball is towards the center. But the velocity of ball is tangential to this circular path all the time. When the whirling is stropped, the string becomes slack and tension in the string becomes zero. The ball no more performs circular motion and the ball moves tangentially to the circle in straight line. Therefore, before letting go, velocity was variable. After letting go, velocity becomes constant.
Heat makes things expand, so in hot water the ballon will get bigger
Answer:
angular resolution = 0.07270° = 1.269 × 
rad
greatest distance from the camera = 118.20 m = 0.118 km
Explanation:
given data
diameter = 0.50 mm = 0.5 × m
distance apart = 15 cm = 15× 
m
wavelength λ = 520 nm = 520 × 
m
to find out
angular resolution and greatest distance from the camera
solution
first we expression here angular resolution that is
sin θ = 
.......................1
put here value λ is wavelength and d is diameter
we get
sin θ = 
θ = 0.07270° = 1.269 × rad
and
distance from camera is calculate here as
θ = 
.................2
I = 
I = 118.20 m = 0.118 km
Mass = 1kg
Distance = 1m
Time = 1s
Force= Mass x Acceleration due to graviy
= 1 x 9.8 = 9.8
Velocity = Distance / time
= 1 / 1 =1m/s
Power = Force x velocity
= 9.8 x 1 = 9.8 W
1/2*2.8*x^{2}=2.8*9.81*1.50
X=5.425
Because K.E=1/2*M*V² and it is equal to P.E in the conservation of energy which means its K.E=P.E
P.E=m*g*h
So K.E equals 1/2*2.8*(5.425)²=41.20
