Calculate the velocity of a car that travels 556 kilometers northeast in 3.4 hours leave your answer in kilometers per hour

An object of mass 300 kg is observed to accelerate at the rate of 4 m/s2. Calculate the force required to produce this accelerat

garik1379 [7]

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 300 × 4

We have the final answer as

Hope this helps you

4 0

3 years ago

An early submersible craft for deep-sea exploration was raised and lowered by a cable from a ship. When the craft was stationary

Alenkinab [10]

Answer:

T = 4200N

Explanation:

When the submersible craft is at rest, the tension in the cable is 6000N.

With this information you can calculate the weight of the craft by summing the forces (the summation of the force is zero because the craft is at rest):

$T-W=0\\\\W=T=6000N$

When the craft is going down with a constant speed, there is a drag force of 1800N. Then, by using the second Newton law you have:

$T-W+F_d=0$ (1)

Fd: drag force

The summation of the forces is zero because the craft moves with constant velocity, that is, there is no acceleration.

You calculate the new tension on the cable by solving the equation (1) for T:

$T=W-Fd=6000N-1800N=4200N$

hence, the tension is 4200N

5 0

3 years ago

Normal atmospheric pressure is 1.013 105 Pa. The approach of a storm causes the height of a mercury barometer to drop by 27.1 mm

Burka [1]

Answer:

The atmospheric pressure is $0.97622\times10^{5}\ Pa$ .

Explanation:

Given that,

Atmospheric pressure $P_{atm}= 1.013\times10^{5}\ Pa$

drop height h'= 27.1 mm

Density of mercury $\rho= 13.59 g/cm^3$

We need to calculate the height

Using formula of pressure

$p = \rho g h$

Put the value into the formula

$1.013\times10^{5}=13.59\times10^{3}\times9.8\times h$

$h =\dfrac{1.013\times10^{5}}{13.59\times10^{3}\times9.8}$

$h=0.76\ m$

We need to calculate the new height

$h''=h - h'$

$h''=0.76-27.1\times10^{-3}$

$h''=0.76-0.027$

$h''=0.733\ m$

We need to calculate the atmospheric pressure

Using formula of atmospheric pressure

$P=\rho g h$

Put the value into the formula

$P= 13.59\times10^{3}\times9.8\times0.733$

$P=0.97622\times10^{5}\ Pa$

Hence, The atmospheric pressure is $0.97622\times10^{5}\ Pa$ .

7 0

3 years ago

Stars which never disappear below the horizon are called__stars. A. Polaris B. visible C. constellation D. circumpolar

miss Akunina [59]

Answer:

D. circumpolar

Explanation:

A circumpolar star is a star, as viewed from a given latitude on Earth, that never sets below the horizon due to its apparent proximity to one of the celestial poles.

-Wikipedia

5 0

4 years ago

A playground merry-go-round with a radius of 1.80 m has a mass of 120 kg and is rotating with an angular speed of 0.350 rev/s. W

stepan [7]

Answer:

1.64 rad/s

Explanation:

Given,

radius of merry-go-round, r = 1.80 m

mass of merry-go-round, M = 120 Kg

angular speed, ω = 0.350 rev/s