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mrs_skeptik [129]
3 years ago
5

Zn + CuSO4 → Cu + ZnSO4

Chemistry
2 answers:
emmasim [6.3K]3 years ago
8 0

Explanation:

pls wat is the question behind this

Taya2010 [7]3 years ago
6 0
What’s the question?
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Which metal reacts quickest in this group (Li, Na, K, Rb and Cs) Why?
Tamiku [17]
Ok so all are in the alkali family also they are all metals and in group 1 but I think the one that might reacts quickest is Li because it has less AMU
3 0
3 years ago
If you have 12 atoms of hydrogen before a chemical reaction, how many atoms of hydrogen will be present
soldi70 [24.7K]

Answer:

《HOPE IT WILL HELP YOU 》

Explanation:

I think the present atom of hydrogen will 1

6 0
4 years ago
What volume of 2.50 M Na2SO4 solution contains 71.0 grams of Na2SO4?
statuscvo [17]

Answer

0.02

Explanation:

7 0
4 years ago
When an atom _______<br> an electron, it charge is negative .
nikitadnepr [17]

Answer:

Gains

Explanation:

If it gains an electron it causes the atom to become negative since electrons are negative and an overall charge of an atom is neutral. Therefore, it would become negative.

Hope this helps :)

3 0
3 years ago
Read 2 more answers
What is the [OH-] of a solution prepared by dissolving 0.0912 g of hydrogen chloride in sufficient pure water to prepare 250.0 m
velikii [3]

Answer: The [OH^-] of a solution is 10^{-12} M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

V_s = volume of solution in ml

moles of HCl = \frac{\text {given mass}}{\text {Molar mass}}=\frac{0.0912g}{36.5g/mol}=0.0025mol

Now put all the given values in the formula of molality, we get

Molarity=\frac{0.0025\times 1000}{250}=0.01

pH or pOH is the measure of acidity or alkalinity of a solution.

HCl\rightarrow H^++Cl^{-}

According to stoichiometry,

1 mole of HCl gives 1 mole of H^+

Thus 0.01 moles of HCl gives =\frac{1}{1}\times 0.01=0.01 moles of H^+

Putting in the values:

[H^+][OH^-]=10^{-14}

[0.01][OH^-]=10^{-14}

[OH^-]=10^{-12}

Thus the [OH^-] of a solution prepared by dissolving 0.0912 g of hydrogen chloride in sufficient pure water to prepare 250.0 ml of solution is 10^{-12} M

8 0
4 years ago
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