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mrs_skeptik [129]
3 years ago
5

Zn + CuSO4 → Cu + ZnSO4

Chemistry
2 answers:
emmasim [6.3K]3 years ago
8 0

Explanation:

pls wat is the question behind this

Taya2010 [7]3 years ago
6 0
What’s the question?
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An archeologist finds a 1.62 kg goblet that she believes to be made of pure gold. She determines that the volume of the goblet i
maxonik [38]
Density (d) which is the quotient when mass (m) is divided by volume (v) is usually reported in terms of g/mL. 
                                  d = m /v
Substituting the known values,
                                d = (1.62 kg) x (1000 g/ 1 kg) / (205 mL)
The answer would be approximately equal to 7.9 g/mL. 
3 0
3 years ago
Read 2 more answers
What is true of a molecule?
nalin [4]

Answer:

All molecules of a compound have one type of atom.FLASE, compounds aren't one type, there compounds

Each molecule of a compound has different properties false

All molecules of a compound have the same properties true

Each atom of a molecule is the same FALSE

Explanation:

hard to say for sure but i think its 3

8 0
3 years ago
Read 2 more answers
A nugget of GOLD has a mass 9.66 gram and a volume of 0.5 cm3, It's density is<br>grams/cm3 *​
dalvyx [7]

Answer:

P=19.32g/cm³

Explanation:

m=9.66g

v=0.5cm³

P=mass/volume (density formula)

=9.66/0.5

=19.32g/cm³

4 0
3 years ago
A sample of gas in which [h2s] = 3.50 m is heated to 1400 k in a sealed vessel. after chemical equilibrium has been achieved, wh
Bond [772]
The value of Kc for the thermal decomposition of H₂S is 2.2 x 10⁻⁴ at 1400 K:
                        2 H₂S(g) ↔     2 H₂(g) + S₂(g)
initial                  3.5 M               0           0
at equilibrium     3.5 M - 2x       2x          x
Kc             = [S₂][H₂]² / [H₂S]² 
2.2 X 10⁻⁴ = x(2x)² / (3.5 - 2x)²
2.2 x 10⁻⁴ = 4 x³ / (3.5)² Assuming x <<<<< 3.5
x = 0.088
Thus [H₂S] = 3.324 M
6 0
3 years ago
How would you prepare 1.00 L of a 0.50 M solution of each of the following?
Lunna [17]

Answer:

Take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water.

Explanation:

Hello,

In this case, for the dilution process from concentrated  12-M hydrochloric acid to 1.00 L of the diluted 0.50M hydrochloric acid, the volume of concentrated HCl you must take is computed by considering that the moles remain constant for all dilution processes as shown below:

n_1=n_2

Which can also be written in terms of concentrations and volumes:

M_1V_1=M_2V_2

Thus, solving for the initial volume or aliquot that must be taken from the 12-M HCl, we obtain:

V_1=\frac{M_2V_2}{M_1} \\\\V_1=\frac{1.00L*0.5M}{12M}\\ \\V_1=0.0417L=41.7mL

It means that you must take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water for such preparation.

Best regards.

6 0
3 years ago
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