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Vaselesa [24]
3 years ago
7

A strong oxidizing agent will donate electrons readily.

Chemistry
2 answers:
alukav5142 [94]3 years ago
8 0
false is the answer to this question.
Triss [41]3 years ago
3 0

<u>Answer:</u> The given statement is false.

<u>Explanation:</u>

Oxidizing agents are defined as the agents that helps in the oxidation of other substance and itself gets reduced. These agents undergo reduction reactions and reduction reaction is the reaction in which an atom gains electrons.

Reducing agents are defined as the agents that helps in the reduction of other substance and itself gets oxidized. These agents undergo oxidation reactions and oxidation reaction is the reaction in which an atom looses electrons.

So, a strong oxidizing agent will gain electrons easily

Hence, the given statement is false.

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Anota una alternativa o solución que se pueda realizar para evitar la escasez de agua:
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Answer:

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3 0
3 years ago
Which of the following are always larger than the neutral atoms from which they are formed?
Anuta_ua [19.1K]

Answer:

A) Cations

Explanation:

a) Cations have a positive charge and are larger than their neutral counterparts!

b) Anions have a negative charge and are smaller than their neutral counterparts

c) Metals can have either a positive or negative charge making it either a cation or an anion

d) Carbon is an element and it can have a charge anywhere from +4 to -4

A good way to remember that cations are positive is to think that CATions are always PAWSitive! ^-^

3 0
3 years ago
Given the following balanced equation, if the rate of O2 loss is 3.64 × 10-3 M/s, what is the rate of formation of SO3? 2 SO2(g)
Fynjy0 [20]

Answer:

Rate of formation of SO₃ [\frac{d[SO_{3}] }{dt}] = 7.28 x 10⁻³ M/s

Explanation:

According to equation   2 SO₂(g) + O₂(g) → 2 SO₃(g)

Rate of disappearance of reactants = rate of appearance of products

                     ⇒ -\frac{1}{2} \frac{d[SO_{2} ]}{dt} = -\frac{d[O_{2} ]}{dt}=\frac{1}{2} \frac{d[SO_{3} ]}{dt}  -----------------------------(1)

    Given that the rate of disappearance of oxygen = -\frac{d[O_{2} ]}{dt} = 3.64 x 10⁻³ M/s

             So the rate of formation of SO₃ [\frac{d[SO_{3}] }{dt}] = ?

from equation (1) we can write

                                   \frac{d[SO_{3}] }{dt} = 2 [-\frac{d[O_{2}] }{dt} ]

                                ⇒ \frac{d[SO_{3}] }{dt} = 2 x 3.64 x 10⁻³ M/s

                                ⇒ [\frac{d[SO_{3}] }{dt}] = 7.28 x 10⁻³ M/s

∴ So the rate of formation of SO₃ [\frac{d[SO_{3}] }{dt}] = 7.28 x 10⁻³ M/s

7 0
4 years ago
Which pair of elements would most likely form a covalent bond
denpristay [2]

Answer:

Nonmetals and nonmetals tend to form covalent bonds.

or

P and S

Explanation:

5 0
3 years ago
How does maximum boiling azeotropic mixture is separated using fractional distillation?
Evgesh-ka [11]

Answer:

By heating the mixture to maximum boiling point and then the solution is distilled at a constant temperature without having a change in composition.

Explanation:

An azeotropic mixture is also called a constant boiling mixture and it is a mixture of two or more liquids whose proportions cannot be altered by simple distillation due to the fact that when an azeotropic mixture is boiled, the vapor has the same proportions of constituents as the unboiled mixture.

Now, maximum boiling azeotropic mixture are the solutions with negative deviations that have an intermediate composition  for which the vapor pressure of the solution is minimum and as a result, the boiling point is maximum. At that point, the solution will distill at a constant temperature without having a change in composition.

4 0
2 years ago
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