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Natalka [10]
3 years ago
8

Which law states that the volume of a gas is proportional to the moles of the gas when pressure and temperature are kept constan

t?
Chemistry
2 answers:
mezya [45]3 years ago
6 0
I believe this would be Avogadro's law which states ''Equal volumes of all gases, at the same temperature and pressure, have the same number of molecules regardless of their chemical nature and physical properties.''
Fiesta28 [93]3 years ago
6 0

Answer:

boyles law

Explanation:

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Write a paragraph on: how Westfield how the rust in their water formed.
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Students have investigated what's going on in the fictional town of Westfield, they learned that the mysterious reddish-brown substance in the water is actually rust, which formed because of a chemical reaction between the iron pipes and the fertilizer substance in the water.

Explanation:

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If the solution feel slippery and has a pH of 12, what is the solution
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___________ is a chemical process that lyses, or splits, molecules by the addition of water functioning in disassembly of polyme
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The answer is: Hydrolysis

Explanation:

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3 years ago
The rock in a lead ore deposit contains 89 % PbS by mass. How many kilograms of the rock must be processed to obtain 1.5 kg of P
Zolol [24]

Answer:

Approximately 1.9 kilograms of this rock.

Explanation:

Relative atomic mass data from a modern periodic table:

  • Pb: 207.2;
  • S: 32.06.

To answer this question, start by finding the mass of Pb in each kilogram of this rock.

89% of the rock is \rm PbS. There will be 890 grams of \rm PbS in one kilogram of this rock.

Formula mass of \rm PbS:

M(\mathrm{PbS}) = 207.2 + 32.06 = 239.26\; g\cdot mol^{-1}.

How many moles of \rm PbS formula units in that 890 grams of \rm PbS?

\displaystyle n = \frac{m}{M} = \rm \frac{890}{239.26} = 3.71980\; mol.

There's one mole of \rm Pb in each mole of \rm PbS. There are thus \rm 3.71980\; mol of \rm Pb in one kilogram of this rock.

What will be the mass of that \rm 3.71980\; mol of \rm Pb?

m(\mathrm{Pb}) = n(\mathrm{Pb}) \cdot M(\mathrm{Pb}) = \rm 3.71980 \times 207.2 = 770.743\; g = 0.770743\; kg.

In other words, the \rm PbS in 1 kilogram of this rock contains \rm 0.770743\; kg of lead \rm Pb.

How many kilograms of the rock will contain enough \rm PbS to provide 1.5 kilogram of \rm Pb?

\displaystyle \frac{1.5}{0.770743} \approx \rm 1.9\; kg.

5 0
3 years ago
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