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2 years ago

8

Which law states that the volume of a gas is proportional to the moles of the gas when pressure and temperature are kept constan

t?

2 answers:

mezya [45]2 years ago

6 0

I believe this would be Avogadro's law which states ''Equal volumes of all gases, at the same temperature and pressure, have the same number of molecules regardless of their chemical nature and physical properties.''

Fiesta28 [93]2 years ago

6 0

Answer:

boyles law

Explanation:

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In order to dry wet clothes, we spread them on a clothline. This is because (i) spreading increases surface area (ii) clothes be

Novosadov [1.4K]

Answer:

this is because spreading it makes more sunlight hit the cloth which results in it drying faster

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2 years ago

What reaction will take place if h2o is added to a mixture of nanh2/nh3? draw the products of the reaction (without sodium ion)?

Maru [420]

When sodium amide i.e. $NaNH_{2}$ reacts with water i.e. $H_{2}O$ results in the formation of sodium hydroxide i.e. $NaOH$ and ammonia $NH_{3}$ .

The chemical reaction is given by:

$NaNH_{2}+H_{2}O\rightarrow NH_{3}+NaOH$

Now, when ammonia i.e. $NH_{3}$ reacts with water results in the formation of ammonium hydroxide i.e. $NH_{4}OH$

The chemical reaction is given by:

$NH_{3}+H_{2}O\rightarrow NH_4OH$

Thus, the products of the above reactions are ammonia and ammonium hydroxide (without sodium ion).

The structures of the products are shown in figure (1): ammonium hydroxide and figure (2) ammonia.

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2 years ago

Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e

notsponge [240]

<u>Answer:</u> The concentration of $Sn^{2+}$ in the cell is $9.0\times 10^{-3}M$

<u>Explanation:</u>

We are given:

<u>Oxidation half reaction:</u> $Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-$ $E^o_{Zn^{2+}/Zn}=-0.76V$

<u>Reduction half reaction:</u> $Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)$ $E^o_{Sn^{2+}/Sn}=-0.136V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Here, tin will undergo reduction reaction and will get reduced.

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=-0.136-(-0.76)=0.624V$

To calculate the EMF of the cell, we use the Nernst equation, which is:

$E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Mn^{2+}]}{[Cu^{2+}]}$

where,

$E_{cell}$ = electrode potential of the cell = 0.660 V

$E^o_{cell}$ = standard electrode potential of the cell = +0.624 V

n = number of electrons exchanged = 2

$[Zn^{2+}]=2.5\times 10^{-3}M$

$[Sn^{2+}]$ = ?

Putting values in above equation, we get:

$0.660=0.624-\frac{0.059}{2}\times \log(\frac{2.5\times 10^{-3}}{[Sn^{2+}})$

$[Sn^{2+}]=9.0\times 10^{-3}M$

Hence, the concentration of $Sn^{2+}$ ions is $9.0\times 10^{-3}M$

3 0

2 years ago

QveST [7]

Metals only and ionic

3 0

2 years ago

Read 2 more answers

Determine the mass of a gold bar that has a density of 19.3 g/cm3 and is 4.72 cm high by 8.21 cm long by 3.98 cm deep.

TEA [102]

The density of the gold is 19.3 grams/cc so each cc weighs 19.3grams. Now we can obtain the volume of gold from the given dimensions ie 4.72x8.21x3.98= 154.23 cc. So for the answer, just multiply the volume or 154.23 x 19.3= 2976.6 grams is the answer.

5 0

2 years ago