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gregori [183]
3 years ago
7

What is the answer to this question?

Mathematics
1 answer:
levacccp [35]3 years ago
5 0
Angle A of triangle ABC will be ...
  ∠A = θ₂ -θ₃ = 77° -26° = 51°
Angle B of triangle ABC will be ...
  ∠B = 180° -θ₂ -θ₁ = 180° -77° -44° = 59°
Then angle C will be ...
  ∠C = 180° -∠A -∠B = 180° -51° -59° = 70°

By the Law of Sines,
  a/sin(∠A) = c/sin(∠C)
  a = c×sin(∠A)/sin(∠C)
  a = (57 yd)×sin(51°)/sin(70°) ≈ 47.14 yd

The distance from B to C is 47.14 yd.
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Attached is a screenshot.

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1. Two triangles have the following congruence statement: ACGI = AMPR Name all 6 pairs of corresponding congruent parts. 1.​
rodikova [14]

Answer:

\angle C \cong \angle M

\angle G \cong \angle P

\angle I \cong \angle R

\overline{CG} \cong \overline{MP}

\overline{GI} \cong \overline{PR}

\overline{CI} \cong \overline{MR}

Step-by-step explanation:

Given the congruence statement ∆CGI \cong ∆MPR, it follows that the corresponding sides of both ∆s are equal, as well as the corresponding vertices or angles. It implies that ∆CGI and ∆MPR are of the same shape and size.

✅Thus, the 6 pairs of the corresponding congruent parts of ∆CGI and ∆MPR are:

\angle C \cong \angle M

\angle G \cong \angle P

\angle I \cong \angle R

\overline{CG} \cong \overline{MP}

\overline{GI} \cong \overline{PR}

\overline{CI} \cong \overline{MR}

3 0
3 years ago
Which of the following appear in the diagram below? Check all that apply. X Z. W O A. _XYZ B. ZYXZ C. w D. YX​
iren2701 [21]

Answer:

A, C, and D.

Step-by-step explanation:

<XYZ appears in the diagram as the vertex angle Y, has two sides, YW and YX that intersect at point Y to form <XYZ.

Thus, <XYZ, line segments YW and YX all appear in the diagram given.

<YXZ does not appear because there's no vertex angle labelled X.

8 0
3 years ago
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