After the collision the magnitude of the momentum of the system is Mv
Given:
mass of 1st object = M
speed of 1st object = v
mass of 2nd object = M
speed of 2nd object = 0
To Find:
magnitude of the momentum after collision
Solution: Product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction. Isaac Newton's second law of motion states that the time rate of change of momentum is equal to the force acting on the particle.
Applying conservation of linear momentum
Mv + M(0) = 2MV
Mv = 2MV
V = v/2
So, after collision momentum is
p = 2MV = 2xMxv/2 = Mv
So, after collision momentum is Mv
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Answer:
<em>J=36221 Kg.m/s</em>
Explanation:
<u>Impulse-Momentum Theorem</u>
These two magnitudes are related in the following way. Suppose an object is moving at a certain speed
and changes it to
. The impulse is numerically equivalent to the change of linear momentum. Let's recall the momentum is given by

The initial and final momentums are, respectively

The change of momentum is

It is numerically equal to the Impulse J


We are given

The impulse the car experiences during that time is

J=-36221 Kg.m/s
The magnitude of J is
J=36221 Kg.m/s
Kinetic energy is greatest at the lowest point of a roller coaster and least at the highest point
Force moves the object but if the same anyone force is applied to both sides then it doesn’t move