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Yuri [45]
3 years ago
8

Two identical satellites orbit the earth in stable orbits. One satellite orbits with a speed v at a distance r from the center o

f the earth. The second satellite travels at a speed that is less than v. At what distance from the center of the earth does the second satellite orbit? a) At a distance that is less than r b)At a distance equal to r. c)At a distance greater than r
Physics
1 answer:
jolli1 [7]3 years ago
7 0

Answer:

c)At a distance greater than r

Explanation:

For a satellite in orbit around the Earth, the gravitational force provides the centripetal force that keeps the satellite in motion:

G\frac{Mm}{r^2}=m\frac{v^2}{r}

where

G is the gravitational constant

M is the Earth's mass

m is the satellite's mass

r is the distance between the satellite and the Earth's centre

v is the speed of the satellite

Re-arranging the equation, we write

r = \frac{GM}{v^2}

so we see from the equation that when the speed is higher, the distance from the Earth's centre is smaller, and when the speed is lower, the distance from the Earth's centre is larger.

Here, the second satellite orbit the Earth at a speed less than v: this means that its orbit will have a larger radius than the first satellite, so the correct answer is

c)At a distance greater than r

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riadik2000 [5.3K]

Answer:

0.6983 m/s

Explanation:

k = spring constant of the spring = 0.4 N/m

L₀ = Initial length = 11 cm = 0.11 m

L = Final length = 27 cm = 0.27 m

x = stretch in the spring = L - L₀ = 0.27 - 0.11 = 0.16 m

m = mass of the mass attached = 0.021 kg

v = speed of the mass

Using conservation of energy

Kinetic energy of mass = Spring potential energy

(0.5) m v² = (0.5) k x²

m v² = k x²

(0.021) v² = (0.4) (0.16)²

v = 0.6983 m/s

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How long does it take a car to cross a 20m bridge if it starts from rest and accelerates at 5 m/s^2?
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The correct answer is 2.8s

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The magnitude of electrical force between a pair of charged particles is ____ as much when the particles are moved half as far a
Gnesinka [82]

The magnitude of the electrical force between a pair of charged particles is 4 Times as much when the particles are moved half as far apart.

This can be easily understood by Columb's law,

F_{new} = \frac{kQ_{1}Q_{2}}{r^{2}}

which state's that the amount of electrical force experienced by two charged particles is inversely proportional to the square of the distance between them.

∴ \frac{F_{new} }{F_{old} } = \frac{Distance_{new}^{2}  }{Distance_{old}^{2}  }

Now, we know the new distance is half the original distance,

F_{new} = \frac{kQ_{1}Q_{2}}{\frac{r}{2}^{2} } \\F_{new} = 4\frac{kQ_{1}Q_{2}}{r^{2}}

F_{new} = 4F_{old}

The electrical force of attraction or electrostatic force of attraction between two charged particles refers to the amount of attractive or repulsive force that exists between the two charges. This can be calculated by Columb's Law.

A charged particle in physics is a particle that has an electric charge. It might be an ion, such as a molecule or atom having an excess or shortage of electrons in comparison to protons. The same charge is thought to be shared by an electron, a proton, or another primary particle.

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Typically, water runs through the baseboard copper tubing and, therefore, fresh hot water is constantly running through the pipi
Bas_tet [7]

Answer: The temperature of the water falls by 3.3°C

Explanation:

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In this example, -2665 J = 193 g x 4.184 J/g°C x dT

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3 years ago
A 1000-kilogram car traveling due east at 15 meters per second hit from behind and receives a forward impulse of 6000 newton-sec
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The change in momentum of the car is 6000 kg m/s

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\Delta p is the change in momentum

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For the car in this problem, the impulse received is

I = 6000 kg m/s (in the forward direction)

Therefore, the change in momentum of the car is equal to this value:

\Delta p = I = 6000 kg m/s (in the forward direction)

We can also calculate what is the new momentum of the car. In fact, the initial momentum is

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And  so, the new momentum is

p_f = p_i + \Delta p = 15,000 + 6,000 = 21,000 kg m/s

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3 years ago
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