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andrew-mc [135]
3 years ago
8

In a front-end collision, a 1500 kg car with shock-absorbing bumpers can withstand a maximumforce of 80 000 N before damage occu

rs. If the maximum speed for a non-damaging collision is4.0 km/h, by how much must the bumper be able to move relative to the car
Physics
1 answer:
Harrizon [31]3 years ago
4 0

Answer:

The bumper will be able to move by 0.01155m.

Explanation:

The magnitude of deceleration of the car in the front end collision.

a = \frac{F_m}{m} \\

a = \frac{80000}{1500} \\

a = 53.33

This is the deceleration of the car that is generated to stop due to a front end collision.

4 km/h = 1.11 m/s

Now, the initial speed of the bumper in the relation of car, Vi = 0

Now, the initial speed of the bumper in the relation of car, Vf = 1.11 m/s

Use the below equation:

s = \frac{(Intitial \ speed)^2 – (Final \ speed)^2}{2a} \\

s = \frac{(1.11)^2 – (0)}{2 \times 53.33} \\

s = 0.01155 \\

Thus, the bumper can move relative to the car is 0.01155 m .

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valentinak56 [21]

Answer:

20573.67N

Explanation:

Given;

mass (m) of the car = 2130kg

angle of inclination Θ = 15⁰

The normal force (F) on the car is given by

F = mgcosΘ

where g is the acceleration due to gravity.

Taking g as 10m/s^{2} and substituting the values of m and Θ into the equation. We have;

F = 2130 x 10 x cos 15⁰

F = 2130 x 10 x 0.9659

F = 20573.67N

Therefore the normal force on the car is 20573.67N

7 0
4 years ago
What is the speed of a 180 g ball if its kinetic energy is 100 J?
Vaselesa [24]

Answer:

Velocity, V = 33.33 m/s

Explanation:

Given the following data;

Mass = 180grams to kilograms = 180/1000 = 0.18 kg

Kinetic energy = 100J

To find the speed;

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

K.E = \frac{1}{2}MV^{2}

Where;

K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

Substituting into the equation, we have;

100 = ½*0.18*V²

Cross-multiplying, we have;

200 = 0.18*V²

V² = 200/0.18

V² = 1111.11

Taking the square root of both sides, we have;

Velocity, V = 33.33 m/s

3 0
3 years ago
What is the efficiency of an engine that exhausts 440 J of heat to a cold reservoir and receives 570 J of heat from a hot reserv
katrin2010 [14]

Answer:

Efficiency = 77%

Explanation:

Input energy = 570 J

Output energy = 440 J

To find the efficiency;

Efficiency = \frac {Out-put \; energy}{In-put \; energy} * 100

Substituting into the equation, we have;

Efficiency = \frac {440}{570} * 100

Efficiency = 0.7719 * 100

Efficiency = 77.19 ≈ 77%

Therefore, the efficiency of the engine is 77 percent.

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3 years ago
How many moles are there in 321g of silver hydroxide?
lesya [120]

Answer:

2.5705594546378 mol

Explanation:

Used this calculator

http://www.endmemo.com/chem/mmass.php

3 0
3 years ago
Jin graduated from college with a degree in zoology, or the study of animals. What company in the STEM career cluster might be i
PIT_PIT [208]

Answer:

b

Explanation:

it is the only one that has to do with animals

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