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Elena L [17]
3 years ago
12

The quotient 97.3hr ÷ 5.5hr contains how many significant digits?A. 4B. 3C. 2D. 1​

Mathematics
1 answer:
aleksandrvk [35]3 years ago
5 0
The answer is.. C I hade trouble with this question and I finally got it
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In a survey of 100 people, 60 like farming, 65 like civil service. Draw a venn-diagram and find the number of people who like fa
MAXImum [283]

Answer:

Ur question is wrong..

Step-by-step explanation:

In a survey of 100 people, 60 like farming and 65 like civil service?

<u>60+65=125</u>..?

7 0
2 years ago
What is the constant term for -2a3b2+5ab5+7b4+8
stiv31 [10]

Hey there!

<u>Constant terms</u> are the terms where no variables are there (only the constant, i.e, the number). So, here the term <em><u>8</u></em><em><u> </u></em><em><u> </u></em>is the constant term because it doesn't have any variables.

Hope it helps ya!

8 0
3 years ago
Dan has a favorite number. His number has the digit 8 in the ones place and 5 in tens place. What is Dan's favorite number.
tino4ka555 [31]
Wouldn't it be 58 or 8.5?
4 0
3 years ago
Read 2 more answers
Help I need to complete this before 3:00 pm
Oduvanchick [21]
It would be 64 x 8 x 8 =
3 0
3 years ago
In a right triangle ΔABC, the length of leg AC = 5 ft and the hypotenuse AB = 13 ft. Find: Chapter Reference b The length of the
Butoxors [25]

Answer:

The length of the angle bisector of angle ∠A is 6.01.

Step-by-step explanation:

It is given that length of leg AC = 5 ft and the hypotenuse AB = 13 ft.

Using pythagoras theorem

(AB)^2=(BC)^2+(AC)^2

(13)^2=(BC)^2+(5)^2

169=(BC)^2+25

BC=12

\sin A=\frac{\text{perpendicular}}{\text{hypotenuse}}

\sin A=\frac{BC}{AB}

A=\sin ^{-1}\frac{12}{13}

A=67.38

Bisector divides the angle in two equal parts, therefore,

A'=\frac{67.38}{2} =33.69

In triangle ACD.

\cos A'=\frac{\text{Base}}{\text{Hypotenuse}}

\cos A'=\frac{AC}{AD}

\cos (33.69^{\circ})=\frac{5}{AD}

0.832=\frac{5}{AD}

AD=\frac{5}{0.832} =6.009\approx 6.01

Therefore the length of the angle bisector of angle ∠A is 6.01.

4 0
3 years ago
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