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3 years ago

If x represents the molar solubility of Ca(OH)2 , what is the correct equation for the K sp ?

Chemistry

1 answer:

mezya [45]3 years ago

3 0

Answer:

Ksp = 4x³

Explanation:

Step 1: Write the reaction for the solution of calcium hydroxide

Ca(OH)₂(s) ⇒ Ca²⁺(aq) + 2 OH⁻(aq)

Step 2: Make an ICE chart

Let "x" be the molar solubility of calcium hydroxide.

Ca(OH)₂(s) ⇒ Ca²⁺(aq) + 2 OH⁻(aq)

I 0 0

C +x +2x

E x 2x

Step 3: Write the expression for the solubility product constant (Ksp)

The solubility product constant is equal to the product of the concentrations of the products raised to their stoichiometric coefficients.

Ksp = [Ca²⁺] × [OH⁻]² = x × (2x²) = x × 4x² = 4x³

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A cube has sides of 11.4 cm. What is its volume?

9966 [12]

It is A) 1,482 cm3 ..............

4 0

4 years ago

1. A 99.8 mL sample of a solution that is 12.0% KI by mass (d: 1.093 g/mL) is added to 96.7 mL of another solution that is 14.0%

Tatiana [17]

Answer:

The mass of PbI2 will be 18.2 grams

Explanation:

Step 1: Data given

Volume solution = 99.8 mL = 0.0998 L

mass % KI = 12.0 %

Density = 1.093 g/mL

Volume of the other solution = 96.7 mL = 0.967 L

mass % of Pb(NO3)2 = 14.0 %

Density = 1.134 g/mL

Step 2: The balanced equation

Pb(NO3)2(aq) + 2 KI(aq) ⇆ PbI2(s) + 2 KNO3(aq)

Step 3: Calculate mass

Mass = density * volume

Mass KI solution = 1.093 g/mL * 99.8 mL

Mass KI solution = 109.08 grams

Mass KI solution = 109.08 grams *0.12 = 13.09 grams

Mass of Pb(NO3)2 solution = 1.134 g/mL * 96.7 mL

Mass of Pb(NO3)2 solution = 109.66 grams

Mass of Pb(NO3)2 solution = 109.66 grams * 0.14 = 15.35 grams

Step 4: Calculate moles

Moles = mass / molar mass

Moles KI = 13.09 grams / 166.0 g/mol

Moles KI = 0.0789 moles

Moles Pb(NO3)2 = 15.35 grams / 331.2 g/mol

Moles Pb(NO3)2 = 0.0463 moles

Step 5: Calculate the limiting reactant

For 1 mol Pb(NO3)2 we need 2 moles KI to produce 1 mol PbI2 and 2 moles KNO3

Ki is the limiting reactant. It will completely be consumed ( 0.0789 moles). Pb(NO3)2 is in excess. There will react 0.0789/2 = 0.03945 moles. There will remain 0.0463 - 0.03945 = 0.00685 moles

Step 6: Calculate moles PbI2

For 1 mol Pb(NO3)2 we need 2 moles KI to produce 1 mol PbI2 and 2 moles KNO3

For 0.0789 moles KI we'll have 0.0789/2 = 0.03945 moles PbI2

Step 7: Calculate mass of PbI2

Mass PbI2 = moles PbI2 * molar mass PbI2

Mass PbI2 = 0.03945 moles * 461.01 g/mol

Mass PbI2 = 18.2 grams

3 0

3 years ago

Cu + 2AgNO3 es002-1.jpg 2Ag + Cu(NO3)2 How many moles of copper must react to form 0.854 mol Ag?

marin [14]

Balance Chemical Equation is as follow,

<span> Cu + 2 AgNO</span>₃ → 2 Ag + Cu(NO₃)₂

According to Balance Equation,

2 Moles of Ag is produced by reacting = 1 Mole of Cu
So,
0.854 Moles of Ag will be produced by reacting = X Moles of Cu

Solving for X,
X = (0.854 mol × 1 mol) ÷ 2 mol

X = 0.427 Moles of Cu
Result:
0.854 Moles of Ag are produced by reacting 0.427 Moles of Cu.

4 0

3 years ago

When a polypeptide is in its native conformation,there are weak interactions between its R groups. However, when it is denatured

Marina86 [1]

Answer:

In the unfolded polypeptide, there are ordered solvation shells of water around the protein

groups. The number of water molecules involved in such ordered shells is reduced when the protein

folds, resulting in higher entropy. Hence, the lower free energy of the native conformation.

Explanation:

4 0

3 years ago

A sample of benzene was vaporized at 25◦C. When 37.5 kJ of heat was supplied, 95.0 g of the liquid benzene vaporized. What is th

grandymaker [24]

Answer:

Enthalpy of vaporization = 30.8 kj/mol

Explanation:

Given data:

Mass of benzene = 95.0 g

Heat evolved = 37.5 KJ

Enthalpy of vaporization = ?

Solution:

Molar mass of benzene = 78 g/mol

Number of moles = mass/ molar mass

Number of moles = 95 g/ 78 g/mol

Number of moles = 1.218 mol

Enthalpy of vaporization = 37.5 KJ/1.218 mol

Enthalpy of vaporization = 30.8 kj/mol

8 0

3 years ago