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amid [387]
3 years ago
10

Loss of a beta particle

Chemistry
1 answer:
zlopas [31]3 years ago
3 0
When a beta particle<span> is emitted from the nucleus the nucleus has one more proton and one less neutron. This means the atomic mass number remains unchanged and the atomic number increases by 1.
We can also say that </span>beta decay<span> is a type of radioactive </span>decay<span> in which a proton is transformed into a neutron inside an atomic nucleus.

</span><span>a) converts a neutron into a proton</span>
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4. If the DNA nitrogen bases were TACCGGAT, how would the other half of
Elena L [17]

Answer:

<u>ATGGCCTA</u>

Explanation:

For this we have to keep in mind that we have a <u>specific relationship between the nitrogen bases</u>:

-) <u>When we have a T (thymine) we will have a bond with A (adenine) and viceversa</u>.

-) <u>When we have C (Cytosine) we will have a bond with G (Guanine) and viceversa</u>.

Therefore if we have: TACCGGAT. We have to put the corresponding nitrogen base, so:

TACCGGAT

<u>ATGGCCTA</u>

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I hope it helps!

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2 years ago
How many moles of nitrogen, N, are in 61.0 g of nitrous oxide, N2O?
Oksana_A [137]

Answer:

2.77 mol N

Explanation:

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61.0 g * 1 mol/44g = (61/44) mol N2O

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                    1 mol         2 mol

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3 years ago
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JWL 3.R 1.096776 x 107 m) L) 384.6 nm C) 683.8 nm D) 1282 nm E) &gt;1500 nm Ans: D According to the Rydberg equation, the line w
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Answer:

91.2 nm

Explanation:

The Rydberg equation is given by the formula

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where

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and n₁ and n₂ are the energy levels of the transion.

We can see from this equation that the wavelength is inversely proportional to the difference of the squares of the inverse of the quantum numbers n₁ and n₂. It follows then that the smallest wavelength will be given when the the transitions are between the greatest separation between n₁ and n₂ whicg occurs when n1= 1 and n₂= ∞ , that is the greater the separation in energy levels the shorter the wavelength.

Substituting for n₁ and n₂ and solving for λ :

  1/λ = 1.0974 x 10⁷ m⁻¹ x ( 1/1² -1/ ∞²)  =  1.0974 x 10⁷ m⁻¹ x ( 1/1² - 0) =

  λ = 1/1.0974 x 10⁷ m = 9.1 x 10⁻8 m = 91.2 nm

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3 years ago
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