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amid [387]
3 years ago
10

Loss of a beta particle

Chemistry
1 answer:
zlopas [31]3 years ago
3 0
When a beta particle<span> is emitted from the nucleus the nucleus has one more proton and one less neutron. This means the atomic mass number remains unchanged and the atomic number increases by 1.
We can also say that </span>beta decay<span> is a type of radioactive </span>decay<span> in which a proton is transformed into a neutron inside an atomic nucleus.

</span><span>a) converts a neutron into a proton</span>
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You have to prepare 100.0 mL of a 0.100 M solution of sodium carbonate. You have a concentrated solution of sodium carbonate tha
Georgia [21]

Answer:

6.9 ml of concentrate

Explanation:

100 ml   of .1 M   will require .01 moles

from a 1.45 M solution,  .01 mole would be

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4 0
1 year ago
Find the vapor pressure of a water solution in which the
zheka24 [161]

Answer:

The vapor pressure in solution is 0,0051 atm

Explanation:

This is the formula for vapor pressure lowering, the colligative property.

P vapor = Pressure sv pure . Xsv

Where Xsv is data.

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Vapor pressure of water, pure is 17.5 mmHg

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5 0
3 years ago
19. What is sthe mass of 6.02 x 1024 atoms
alekssr [168]

The mass of magnesium in 6.02 \times 10^{24} atoms is 240 g.

Answer: Option A

<u>Explanation:</u>

First, we have to convert the atoms to moles of magnesium.

We know that 6.02 \times 10^{24} atoms are present in 1 mole of magnesium. So,

    \text { 1 atom }=\frac{1}{6.02 \times 10^{24}} \text { moles }

    6.02 \times 10^{24} \text { atoms }=\frac{6.02 \times 10^{24}}{6.02 \times 10^{23}} \text { moles }=10 \text { moles }

Thus,

     Mass of M g= molar mass of M g \times No. of moles of M g

     \text { Mass of } M g=24 \times 10=240 g

Thus, 240 g of Magnesium is present in 6.02 \times 10^{24} atoms.

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Porque a las vacunas los cientificos las llaman reactivos.​
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