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3 years ago

When more than one wave is in the same location at the same time, then there is _____ between the waves?

1 answer:

4 0

The sentence can be completed as follows:
"<span>When more than one wave is in the same location at the same time, then there is interference between the waves"

In fact, when there are two or more waves in the same location at the same time, their amplitude sum together. The two extreme possibilities are:
- costructive interference: the two waves arrive on phase at the same location (=their crests arrive at the same location at the same time). In this case, the amplitudes of the waves sum together and the resultant wave has greater amplitude.
- destructive interference: the two waves arrive out of phase at the same location. In this case, the amplitudes of the two waves cancel out, and the resultant wave has amplitude zero.</span>

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3 years ago

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3 years ago

Read 2 more answers

A skateboarder shoots off a ramp with a velocity of 5.1 m/s, directed at an angle of 55° above the horizontal. The end of the ra

ExtremeBDS [4]

Answer

given,

initial velocity of skateboard = 5.1 m/s

angle above the horizontal = 55°

height of the ramp = 1 m

a) maximum height of projectile

$H = \dfrac{u^2sin^2 \theta}{2g}$

$H = \dfrac{5.1^2\times sin^2 55^0}{2\times 9.81}$

H = 0.889 m

the maximum height of the skateboard above the ground

= 1 + 0.889

= 1.889 m

b) time to reach the height

$t = \dfrac{u\ sin\theta}{g}$

$t = \dfrac{5.1\ sin55^0}{9.8}$

t = 0.426 s

horizontal distance = u cos θ × t

= 5.1 × cos 55° × 0.426

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3 years ago

A stuntwoman is going to attempt a jump across a canyon that is 77 m wide. The ramp on the far side of the canyon is 25 m lower

liq [111]

initial speed of the stuntman is given as

$v = 28 m/s$

angle of inclination is given as

$\theta = 15 degree$

now the components of the velocity is given as

$v_x = 28 cos15 = 27.04 m/s$

$v_y = 28 sin15 = 7.25 m/s$

here it is given that the ramp on the far side of the canyon is 25 m lower than the ramp from which she will leave.

So the displacement in vertical direction is given as

$\delta y = -25 m$

$\delta y = v_y * t + \frac{1}{2} at^2$

$-25 = 7.25 * t - \frac{1}{2}*9.8* t^2$

by solving above equation we have

$t = 3.12 s$

Now in the above interval of time the horizontal distance moved by it is given by

$d_x = v_x * t$

$d_x = 27.04 * 3.12 = 84.4 m$

since the canyon width is 77 m which is less than the horizontal distance covered by the stuntman so here we can say that stuntman will cross the canyon.

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3 years ago

What is the total energy equation?

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The total energy equation would be Kinetic energy+Potential energy

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3 years ago