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Otrada [13]
3 years ago
13

What is the approximate value of the gravitational force between a 73 kg astronaut and a 7.1×104 kg spacecraft when they're 89 m

apart?
Physics
1 answer:
Luden [163]3 years ago
5 0

Answer:

F = 4.3671 * 10^{-8}\ Newtons

Explanation:

The gravitational force between two corpses is given by the following equation:

F = GMm/d^2

Where F is the force, G is the gravitational constant

(G = 6.67408*10^{-11}\ m^3kg^{-1}s^{-2}), M and m are the masses of the corpses and d is the distance between them.

So we have that:

F = 6.67408*10^{-11} * 7.1*10^4 * 73/89^2

F = 4.3671 * 10^{-8}\ Newtons

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4 x 10^-9F

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A wave of wavelength 0.3 m travels 900 m in 3.0 s. Calculate its frequency.
zzz [600]

Answer:

1000 Hz

Explanation:

<em>The frequency would be 1000 Hz.</em>

The frequency, wavelength, and speed of a wave are related by the equation:

<em>v = fλ ..................(1)</em>

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Making f the subject of the formula:

<em>f = v/λ.........................(2)</em>

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6 0
3 years ago
The current supplied by a battery as a function of time is I(t) = (0.88 A) e^(-t*6 hr). What is the total number of electrons tr
Degger [83]

Answer:

e. 1.2 x 10²³

Explanation:

According to the problem, The current equation is given by:

I(t)=0.88e^{-t/6\times3600s}

Here time is in seconds.

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The relation between current and number of charge carriers is:

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Here the limits of integration is from 0 to infinite. So,

q=\int\limits {0.88e^{-t/6\times3600s}}\, dt

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q = N e

Here e is electronic charge and its value is 1.69 x 10⁻¹⁹ C.

N = q/e

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N= \frac{1.9\times10^{4} }{1.69\times10^{-19}}

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8 0
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Ad libitum [116K]

Answer:

Acceleration

Explanation:

acceleration because it has magnitude but no direction

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4 years ago
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