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drek231 [11]
3 years ago
15

Please help. This is summer homework that's due in 2 days!

Mathematics
1 answer:
iVinArrow [24]3 years ago
4 0
Split the surface area into geometric shapes as shown in the figure below.

Top part
The area of one triangle is
A₁ = (1/2)*(10 cm)*(4 cm) = 20 cm²
There are 3 of these triangles.

Vertical sides..
The area of one vertical side is
A₂ = (10 cm)*(6 cm) = 60 cm²
There 3 of them.

Bottom part
The triangle is equilateral with each side  = 10 cm, and each angle = 60 deg.
The area is (from the Law of Sines)  equal to
A₃ = (1/2)(10 cm)*(10 cm)*sin(60) = 43.3 cm²

The total surface area is
3A₁ + 3A₂ + A₃
= 3*20 + 3*60 + 4.3
= 283.3 cm²

Answer: The surface area is  283.3 cm²

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Find the slope and y-intercept of the line
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C

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~**Will mark brainliest **~<br> For the correct answers to all three questions
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a)

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b)

\dfrac{21}{32}\cdot\dfrac{39}{120}\cdot\dfrac{40}{65}=\dfrac{21}{32}\cdot\dfrac{3\cdot13}{2\cdot2\cdot2\cdot3\cdot5}\cdot\dfrac{2\cdot2\cdot2\cdot5}{5\cdot13}=\\\\\\=\dfrac{3\cdot7}{32}\cdot\dfrac{13}{2\cdot2\cdot2\cdot5}\cdot\dfrac{2\cdot2\cdot2}{13}=\dfrac{21}{32}\cdot\dfrac{1}{5}\cdot\dfrac{1}{1}=\dfrac{21}{160}

c)

\dfrac{15}{90}\cdot\dfrac{36}{75}\cdot\dfrac{27}{42}=\dfrac{3\cdot5}{2\cdot3\cdot3\cdot5}\cdot\dfrac{2\cdot2\cdot3\cdot3}{3\cdot5\cdot5}\cdot\dfrac{3\cdot3\cdot3}{2\cdot3\cdot7}=\\\\\\=\dfrac{1}{2\cdot3}\cdot\dfrac{2\cdot2\cdot3}{5\cdot5}\cdot\dfrac{3\cdot3}{2\cdot7}=\dfrac{1}{1}\cdot\dfrac{2}{5\cdot5}\cdot\dfrac{3\cdot3}{2\cdot7}=\dfrac{1}{25}\cdot\dfrac{9}{7}=\dfrac{9}{175}

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