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enot [183]
3 years ago
8

The reactants A and B react completely in a sealed container to form a product. What is the mass of the product of the reaction

between 3.0 grams of reactant A and 5.7 grams of reactant B?
Chemistry
1 answer:
Len [333]3 years ago
3 0

Answer:

I'm pretty sure it is 8.7

Explanation:

and btw you are fineeee

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How do machines transfer and convert energy
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7 0
4 years ago
If the ka of a monoprotic weak acid is 1.2 × 10-6, what is the ph of a 0.40 m solution of this acid?
frez [133]
First, we write out a balanced equation.
HA <--> H(+) + A(-)

Next, we create an ICE table

        HA     <-->      H+     +    A-
[]i     0.40M            0M           0M
Δ[]    -x                   +x            +x
[]f     0.40-x             x              x

Next, we write out the Ka expression.

Ka = [H+][A-]/[HA]

Ka = x*x/(0.40-x) 

However, because Ka is less than 10^-3, we can assume the amount of dissociation is negligible. Thus,

Assume 0.40-x ≈ 0.40

Therefore, 1.2x10^-6 = x^2/0.40

Then we solve for the [H+] concentration, or x

\sqrt{0.40(1.2*10^{-6})} =x

x=6.93x10^-4

Next, to find pH we do 

pH = -log[H+]

pH = -log[6.93x10^-4]

pH = 3.2
5 0
3 years ago
Which of the following does not contain ionic bonds?
Nutka1998 [239]

Answer:

Sulfur dioxide

Explanation:

8 0
3 years ago
When the products of a reaction are hotter than the reactants:
kobusy [5.1K]
A.) The reaction is Exothermic
5 0
3 years ago
How many moles of N20 gas would have a volume of 3.8 L at 460 mmHg and 77°C?
Citrus2011 [14]

<u>We are given:</u>

Volume of gas = 3.8 L

Pressure = 460 mmHg

Temperature = 77°c = (77+273)K = 350K

<u>Converting the pressure to atm:</u>

Pressure(in atm)  = Pressure(in mmHg) / 760

Pressure = 460/760 = 0.6 atm

<u>Finding the number of moles:</u>

using the ideal gas equation:

PV = nRT                                         [where R is the universal gas constant]

<em>replacing the given values in this equation</em>

(0.6)(3.8) = n(0.082)(350)

n = (0.6*3.8)/(0.082*350)

n = 0.08 moles

7 0
3 years ago
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