Answer:
I have a screenshot of this.
Explanation:
Answer:
Explanation:
2500 rpm = 2500 / 60 rps ( revolution per second )
= 41.67 rps .
power output = 500 kW
thermal efficiency = 20 %
power input = (100 /20) x 500 kW
= 2500 kW .
work done per second = 2500 kJ
work done per cycle = 2500 / 41.67
= 60 kJ .
Answer:
Time taken = 444.4s
Explanation:
how long = the time taken
and from the definition of speed,we have that :
Average speed = distance ( m)
_____________
time (s)
therefore,Time = distance (m) / average speed (m/s)
Time = 8000/18
Time = 444.4 (s)
I hope that the attachment helps you..
To develop this problem we will apply the concepts related to Sound Intensity. This can be defined as the power carried by sound waves per unit area in a direction perpendicular to that area. Mathematically it can be written as,
![\Delta L = 10log(n)](https://tex.z-dn.net/?f=%5CDelta%20L%20%3D%2010log%28n%29)
= Level Difference
n = Number of equal loud sound sources
n = 15
Therefore replacing we have,
![\Delta L = 10 log (n)\\\Delta L = 10 log (15)\\\Delta L = 10*1.176\\\Delta L = 11.76dB](https://tex.z-dn.net/?f=%5CDelta%20L%20%3D%2010%20log%20%28n%29%5C%5C%5CDelta%20L%20%3D%2010%20log%20%2815%29%5C%5C%5CDelta%20L%20%3D%2010%2A1.176%5C%5C%5CDelta%20L%20%3D%2011.76dB)
Therefore over 100dB the total difference intensity level would be
![L_T = L_0 -\Delta L](https://tex.z-dn.net/?f=L_T%20%3D%20L_0%20-%5CDelta%20L)
Here,
![L_0 = \text{ Total intensity}](https://tex.z-dn.net/?f=L_0%20%3D%20%5Ctext%7B%20Total%20intensity%7D)
![\L_T = 100 -11.76](https://tex.z-dn.net/?f=%5CL_T%20%3D%20100%20-11.76)
![_T= 88.24dB](https://tex.z-dn.net/?f=_T%3D%2088.24dB)
The intensity level generated by one engine is
![L_T = 88.44dB](https://tex.z-dn.net/?f=L_T%20%3D%2088.44dB)