Answer:
h = 16.9 m
Explanation:
When a ball is thrown upward, its velocity gradually decreases, until it stops for a moment, when it reaches the maximum height, while its height increases. Thus, the law conservation of energy states in this case, that:
Kinetic Energy Lost by Ball = Potential Energy Gained by Ball
(0.5)m(Vf² - Vi²) = mgh
h = (0.5)(Vf² - Vi²)/g
where,
Vf = Final Speed of Ball = 0 m/s (Since, ball stops for a moment at highest point)
Vi = Initial Speed of Ball = 18.2 m/s
g = acceleration due to gravity = - 9.8 m/s² ( negative for upward motion)
h = maximum height the ball can reach = ?
Therefore, using values in the equation, we get:
h = (0.5)[(0 m/s)² - (18.2 m/s)²]/(-9.8 m/s²)
<u>h = 16.9 m</u>
Answer:
The heat flow through the slab in a day is 432,000 J
Explanation:
Q = kA∆T/t
Q is rate of heat flow
k is thermal conductivity = 0.1 J/s/m.°C
A is area = 100 cm^2 = 100 cm^2 × (1 m/100 cm)^2 = 0.01 m^2
∆T is temperature difference = 100 °C
t is thickness = 2 cm = 2/100 = 0.02 m
Q = 0.1×0.01×100/0.02 = 5 J/s
In a day, there are 24×60×60 = 86,400 s
Heat flow in a day = 5 J/s × 86,400 s = 432,000 J
I would say none of the options. This evidence does not support the hypothesis, but it doesn't contradict it, however it is related to the hypothesis. I guess what I'm trying to say is that the evidence isn't sufficient enough to make any definitive comments about the hypothesis. I don't think that you can just decide on whether to accept or reject your hypothesis based on observation alone and moreover, an observation that was made once. You need to make many observations, at certain points every day, in the same area of reef and the same area of open sea for a certain amount of time to gain a good amount of data (you could split up areas of reef and open sea on a particular coast into square meters or what ever unit you want and dedicate 3 days to each area you've split up) then you can perform a statistical test that suits the model of your data. I hope this helps in some way and I'm sorry it's so long. I couldn't think of a shorter way to say this.
Although you walked (14+9)= 23 meters of distance, you ended up only 16.64 meters from where you started. That's your "displacement".
Velocity = (displacement / (time)
Velocity = (16.64m)/(180s)
Velocity = 0.0925 m/s roughly Southwest.
(That's about 3.6 INCHES per second. Apparently, you really NEED that mocha java and it's associated drug.)
Answer:
The displacement after 4 more complete oscillations is 10.56cm
Explanation:
Initial displacement, Xo=10cm
After one complete oscillation displacement X1=7.36cm
Change in displacement = Xo-X1=( 10-7.36)can =2.64cm
1 oscillation =2.64cm
4 oscillations= 4×2.64=10.56cm
