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3 years ago

I need to know what is a product and a reactant in this please

Physics

1 answer:

Alekssandra [29.7K]3 years ago

8 0

Answer:

2Mg + O2 = Reactant | 2MgO = Product

Explanation:

It is pretty simple, look:

The elements that are being added (or in the majority of the cases, the one who are in the left side) are always the Reactant.

The other side is the product of the reactants.

It is like a mathematic formula

We some the numbers to get the result, the numbers are the reactants and the result is the product.

(I hope you didn´t get confused)

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How long will it take a plane to fly 1256km<br> if it travels 500km/hr?

expeople1 [14]

Answer:

<h3>The answer is 2.51 s</h3>

Explanation:

The time taken can be found by using the formula

$t = \frac{d}{v} \\$

d is the distance

v is the velocity

From the question we have

$t = \frac{1256}{500} \\ = 2.512$

We have the final answer as

Hope this helps you

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3 years ago

1. What do you notice or wonder about ultrasound imaging? (black and white pictures)

a_sh-v [17]

Answer:

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Explanation:

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3 years ago

A team of ecologists are studying four different ecosystems with varying levels of biodiversity. The ecologists categorize the d

Ann [662]

Answer:

B. Ecosystem B, because its high species diversity could have resulted from increased competition among its members.

Explanation:

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3 years ago

How much force was applied to an object if was moved 2 meters and the work done on the object was 8 joules?

serious [3.7K]

Answer:

The answer is 4N or B

Explanation:

Just the equation W = F x D.

We have W = 8 J and D = 2 m using algebra ....

8J/2m = F ... F = 4.

6 0

3 years ago

Read 2 more answers

The plug has a diameter of 30 mm and fits within a rigid sleeve having an inner diameter of 32 mm. Both the plug and the sleeve

Katena32 [7]

Answer:

P=740 KPa

Δ=7.4 mm

Explanation:

Given that

Diameter of plunger,d=30 mm

Diameter of sleeve ,D=32 mm

Length .L=50 mm

E= 5 MPa

n=0.45

As we know that

Lateral strain

$\varepsilon _t=\dfrac{D-d}{d}$

$\varepsilon _t=\dfrac{32-30}{30}$

$\varepsilon _t=0.0667$

We know that

$n=-\dfrac{\epsilon _t}{\varepsilon _{long}}$

$\varepsilon _{long}=-\dfrac{\epsilon _t}{n}$

$\varepsilon _{long}=-\dfrac{0.0667}{0.45}$

$\varepsilon _{long}=-0.148$

So the axial pressure

$P=E\times \varepsilon _{long}$

$P=5\times 0.148$

P=740 KPa

The movement in the sleeve

$\Delta =\varepsilon _{long}\times L$

$\Delta =0.148\times 50$

Δ=7.4 mm

6 0

3 years ago