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4 years ago

I need to know what is a product and a reactant in this please

Physics

1 answer:

Alekssandra [29.7K]4 years ago

8 0

Answer:

2Mg + O2 = Reactant | 2MgO = Product

Explanation:

It is pretty simple, look:

The elements that are being added (or in the majority of the cases, the one who are in the left side) are always the Reactant.

The other side is the product of the reactants.

It is like a mathematic formula

We some the numbers to get the result, the numbers are the reactants and the result is the product.

(I hope you didn´t get confused)

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A class 9 student booked his ticket to moon. His travel company

jasenka [17]

Answer: LET'S TAKE GRAVITY ON EARTH AS 10 N/KG AND ON MOON AS 0.6 N/KG

a) weight=15kgx10N/kg

= 150N

b) weight=15x0.6=9N

c) mass=is the same so 15kg

d) mass is measured in kg, weight in NEWTONS OR $KG M/S^{2}$

e) when the gravitational force is zero

Explanation:

7 0

3 years ago

A vertical bar magnet is dropped through the center of a horizontal loop of wire, with its north pole leading. At the instant wh

AlladinOne [14]

Answer:

The induced current will be counterclockwise.

Explanation:

Magnetic field lines always begin on north poles and end on south poles. This means that there is an increase of magnetic field lines going into the plane of the loop. The induced current will be counterclockwise to oppose this change.

7 0

4 years ago

Read 2 more answers

Which of the following is not an example of work??

agasfer [191]

I would say B

Because technically if your just holding it your not doing anything

-May

5 0

3 years ago

A 90-meter train travels at a constant speed of 10 meters per second. How long will it take to cross a 0.06 bridge?

salantis [7]

Answer:

The time taken for the train to cross the bridge is 9.01 s

Explanation:

Given;

length of the train, L₁ = 90 m

length of the bridge, L₂ = 0.06 m

speed of the train, v = 10 m/s

Total distance to be traveled, = L₁ + L₂

= 90 m + 0.06 m

= 90.06 m

Time of motion = Distance / speed

Time of motion = 90.06 / 10

Time of motion = 9.006 s ≅ 9.01 s

Therefore, the time taken for the train to cross the bridge is 9.01 s

5 0

3 years ago

A 2.1 kg steel ball strikes a massive wall at 13.2 m/s at an angle of 64.8 ◦ with the perpendicular to the plane of the wall. It

solong [7]

Answer:

112 N

Explanation:

going through the question you would notice that some detail is missing, using search engines u was able to find a similar question on "https://socratic.org/questions/a-2-3-kg-steel-ball-strikes-a-wall-with-a-speed-of-8-5-m-s-at-an-angle-of-64-wit"

and here is the question i found

"A 2.3 kg steel ball strikes a wall with a speed of 8.5 m/s at an angle of 64⁰ with the surface. It bounces off with the same speed and angle. If the ball is in contact with the wall for 0.448 s. What is the average force exerted by the ball?"

you would notice that there is a change in the values from the question posted, hence we would only take the following part to complete our question, " If the ball is in contact with the wall for 0.448 s what is the average force exerted by the ball?" while retaining all original detail.

solution

mass of ball (m) = 2.1 kg

speed of ball (v) = 13.2 m/s

angle of contact (p) = 64.8°

time of contact (t) = 0.448 s

What is the average force exerted by the ball?

The average force exerted by the ball = $\frac{change in momentum}{change in time}$

where

The momentum changes only the direction perpendicular to the wall, hence the component of momentum perpendicular to the wall = m x v x sin (p) = 2.1 x 13.2 x sin 64.8 = 25.1 kg.m/s

since the ball strikes the wall and bounces off it with the same speed

and at the same angle, the component of momentum acting

perpendicular to the wall remains the same while hitting and leaving

the wall but in opposite directions.

Hence the component of momentum acting perpendicular to the wall while hitting and leaving the wall will be 25.1 kg.m/s and -25.1 kg.m/s respectively.

change in momentum = 25.1 - (-25.1) = 25.1 + 25.1 = 50.2 kg.m/s

change in time = 0.448 s

now substituting the above into the equation we have

The average force exerted by the ball = $\frac{50.2}{0.448}$ = 112 N

6 0

4 years ago