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anygoal [31]
3 years ago
7

By looking at the location of f on the periodic table what can you know about fluorine?

Chemistry
2 answers:
Musya8 [376]3 years ago
3 0
by looking at the periodic table I think Florian is a gas because it's important like in the bottom
Vilka [71]3 years ago
3 0
From its location on the periodic table, you can learn many things about fluorine:

* it has 7 valence electrons
* it is a halogen
* it is very reactive
* it is also very electronegative
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Who arranged the elements according to atomic mass, and used the arrangement to predict the properties of missing elements.
Karolina [17]

Answer:

i think it's C

Explanation:

But if it's wrong,im so sorry

6 0
2 years ago
Read 2 more answers
How many Mol are in 4.000 grams of MgCl2 ?
grigory [225]

Answer:

The number of mol is: 0, 042 mol in 4 grams of MgCl2

Explanation:

We calculate the weight of 1 mol of MgCl2:

Weight 1mol of MgCl2= weight Mg + (weight Cl)x  2=

24, 3 grams + 2 x 35, 5 grams = 95, 3 grams/mol MgCl2

95, 3 grams------1 mol MgCl2

4 grams      -------x = (4 grams x1 mol MgCl2)/ 95, 3 grams= 0, 04197 mol MgCl2

4 0
3 years ago
In general, the rate of evaporation increases with ___________.
mars1129 [50]

Answer:

heat increase,   pressue loss,  altitude gain,  

Explanation:

6 0
2 years ago
A solution of KMnO4 has an absorbance of 0.539 when measured in the colorimeter. Determine the concentration of the KMnO4 given
loris [4]

Answer:

Concentration of unknown solution is 0.0416 M

Explanation:

As we know  

Absorbance is equal to the product of molar absorptivity of KMnO4 m, path length and concentration

From the given set of graphical data, it is clear that the absorbance vs concentration is a straight line.  

From the graph, we can obtain-  

Y = 5.73 X – 0.0065

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0.232 = 5.73 X – 0.0065

X = 0.0416  

Concentration of unknown solution is 0.0416 M

6 0
2 years ago
Calculate the ΔHrxn for the following
Vesnalui [34]

Answer:

2 NO (g) → N2 (g) + O2 (g)

2 NOCl (g) → 2 NO (g) + Cl2 (g)

____________________________

2NOCl (g) ⟶ N2 (g) + O2 (g) + Cl2 (g)

ΔH = [90.3 kJ x 2 x -1] +  [-38.6 kJ x -1 x 2] = -103.4 kJ

The ΔH for the reaction is -103.4 kJ

6 0
3 years ago
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