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Dima020 [189]
3 years ago
6

What would barium do to obtain a noble gas structure?

Chemistry
2 answers:
ExtremeBDS [4]3 years ago
6 0
Ba 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s² → [Xe]6s²

Ba - 2e⁻ → Ba⁺²  [Xe]
Leno4ka [110]3 years ago
5 0

Answer:

Lose two electrons.

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The atomic radius of a silver atom is 1.44 x 10-10. Give the
professor190 [17]

Answer:

0.144 nm

Explanation:

Silver's electronic configuration is (Kr)(4d)10(5s)1, and it has an atomic radius of 0.144 nm.

5 0
3 years ago
815 yd to km (need 3 sig fig)
SpyIntel [72]

<u>Answer:</u> The correct answer is 0.745 km

<u>Explanation:</u>

We are given:

A numerical value of 815 yards

To convert this into kilometers, we use the conversion factor:

1 km = 1093.6 yards

Converting the given value into kilometers, we get:

\Rightarrow 815yd\times \frac{1km}{1093.6yd}=0.745km

Hence, the correct answer is 0.745 km

5 0
3 years ago
For an endothermic reaction, how will the value for Keq change when the temperature is increased?
Nataly [62]
I put the answer <em>C: Keq will increase</em>, on PLATO. Hope this works for you!
4 0
3 years ago
Read 2 more answers
Carbon burns in the presence of oxygen to give carbon dioxide. Which chemical equation describes this reaction?
Alex73 [517]
Your answer is B.
Because it says that that carbon burns in presence of oxygen (C+O) which is equal ( => ) to Carbon Dioxide (CO_{2})
3 0
4 years ago
Read 2 more answers
How much heat is absorbed/released when 20.00 g of NH3(g) reacts in the presence of excess O2 (g) to produce NO (g) and H2O (l)
FrozenT [24]

Answer:

a. 342.9 kJ of heat are absorbed.

Explanation:

Calculation of the moles of NH_3 as:-

Mass = 20.00 g

Molar mass of NH_3 = 17.031 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{20.00\ g}{17.031\ g/mol}

Moles= 1.1743\ mol

Given that:- \Delta H=+1168\ kJ

It means that 1 mole of NH_3 undergoes reaction and absorbs 1168\ kJ of heat

So,

1168 mole of NH_3 undergoes reaction and absorbs 1168\times 1168\ kJ of heat

<u>Amount of heat absorbed = + 342.9 KJ</u>

7 0
3 years ago
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