Sắp xếp các hợp chất: HF, HI, HBr, HCl theo chiều giảm dần tính axit.

What are the differences between simple, compound, and electron microscopes? WILL GET BRAINIEST!

timurjin [86]

I think the answer is= simple/uses surrounding light source and is restricted in magnification.
compound uses an electrical light source but is restricted in magnification also. an electron microscope has electrical magnification and light source so you can see smaller cells when dyed the rt. color..plse double check, good luck..

5 0

2 years ago

A power plant is driven by the combustion of a complex fossil fuel having the formula C11H7S. Assume the air supply is composed

AlekseyPX

(a) 4C_11 H_7S + 55O_2 → 44CO_2 + 14H_2O + 4SO_2 + 20.68N_2;

(b) 4C_11 H_7S + 66O_2 → 44CO_2 + 14H_2O + 4SO_2 + 248.2N_2 + 11O_2;

(c) 23 900 kg air; (d) air:fuel = 10.2; (e) air:fuel = 12.2:1

(a) Balanced equation including N_2 from air

The balanced equation ignoring N_2 from air is

4C_11 H_7S + 55O_2 → 44CO_2 + 14H_2O + 4SO_2

Moles of N_2 =55 mol O_2 × (3.76 mol N_2/1 mol O_2) = 206.8 mol N_2

Including N_2 from air, the balanced equation is

4C_11 H_7S + 55O_2 → 44CO_2 + 14H_2O + 4SO_2 + 206.8N_2

(b) Balanced equation for 120 % stoichiometric combustion

Moles of O_2 = 55 mol O_2 × 1.20 = 66.00 mol O_2

Excess moles O_2 = (66.00 – 55) mol O_2 = 11.00 mol O_2

Moles of N_2 = 66.00 mol O_2 × (3.76 mol N_2/1 mol O_2) = 248.2 mol N_2

The balanced equation is

4C_11 H_7S + 66O_2 → 44CO_2 + 14H_2O + 4SO_2 + 248.2N_2 + 11O_2

(c) Minimum mass of air

Moles of O_2 required = 1700 kg C_11 H_7S

× (1 kmol C_11 H_7S/185.24 kg C_11 H_7S) × (55 kmol O_2/4 kmol C_11 H_7S)

= 126.2 kmol O_2

Mass of O_2 = 126.2 kmol O_2 × (32.00 kg O_2/1 kmol O_2) = 4038 kg O_2

Mass of N_2 required = 126.2 kmol O_2 × (3.76 kmol N_2/1 kmol O_2)

× (28.01 kg N_2/1 kmol N_2) = 13 285 kg N_2

Mass of air = Mass of N_2 + mass of O_2 = (4038 + 13 285) kg = 17 300 kg air

(d) Air:fuel mass ratio for 100 % combustion

Air:fuel = 17 300 kg/1700 kg = 10.2 :1

(e) Air:fuel mass ratio for 120 % combustion

Mass of air = 17 300 kg × 1.20 = 20 760 kg air

Air:fuel = 20 760 kg/1700 kg = 12.2 :1

6 0

2 years ago

How many daughter cells are created from mitosis and cytokinesis?

mixas84 [53]

Mitosis creates 2 daughter cells which are diploid. These products are genetically identical. Meiosis produces 4 daughters cells which are haploid. These products are genetically different.

4 0

3 years ago

What happens when the student use a straw to blow a stream of air between the papers?

klasskru [66]

Actualy the answer is Lower pressure causes the papers to come closer together.

Please mark brainiest if this is correct and helpful.

3 0

3 years ago

2. A flask and stopper have a mass of 110.525 g. A 50.0-mL sample of gasoline is transferred to the flask, and the flask, stoppe

Dominik [7]

Answer:

0.690 g/mL

Explanation:

Density is the ratio of mass to volume:

gasoline mass = (flask+gas mass) - (flask mass) = 145.028 g -110.525 g

gasoline mass = 34.503 g

Density = (gas mass)/(gas volume) = (34.503 g)/(50.0 mL)

Density = 0.690 g/mL

_____

The least-precise number in this calculation is the sample volume, which has 3 significant figures. Thus, the answer is good only to 3 significant figures.

8 0

3 years ago