1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
GarryVolchara [31]
3 years ago
15

Answer the two questions by using the pictures, thanks!

Chemistry
1 answer:
vladimir2022 [97]3 years ago
7 0

Answer:

  • See descriptions below.

Explanation:

<h2>Part A:</h2>

The football was launched by the girl. This is, the girl applied a <em>force </em>over the football and it started to move.

Newton's second law of<em> motion</em> tell us that the <em>net force </em>on an object is proportional to the product of the the mass of the object and the acceleration it acquires.

Then, the force applied by the girl on the football caused it to accelerate: it passed from rest to have some speed.

The same happens to the baseball lauched by the boy. It accelerated due to the force applied by the boy.

The acceleration of each ball can be calculated using Newton's second law of motion:

       a=\dfrac{Net\text{ }Force}{mass}

Thus, if you assume that both the girl and the boy applied the same force to their respective balls, the baseball, which has less mass, would acquired a greater accelaration than the football.

<h2>Part B.</h2>

After the<em> football</em> and<em> baseball leave the students' hands</em>, the only force acting on them is the force of gravity which is vertically downward.

If there was not gravitational and other forces acting after the sutdents launched the balls, they  would continue to travel in the same direction and with the same speed that it started to move.

Due to the gravitational force, the combination of the initial speed acquired by each ball, by the force applied by each student, and the downward acceleration after the balls left the students' hands make that the motion of the balls be parabolic.

You might be interested in
Pls help me 20 points ty
qaws [65]

Answer:

what do you need help with i cant see it

Explanation:

6 0
3 years ago
Read 2 more answers
Which equation shows how to calculate how many grams (g) of KOH would be needed to fully react with 4 mol Mg(OH)2? The balanced
bazaltina [42]
Mole ratio:

MgCl₂ + 2 KOH = Mg(OH)₂ + 2 KCl

2 moles KOH ---------------- 1 mole Mg(OH)₂
moles KOH ------------------- 4 moles Mg(OH₂)

moles KOH = 4 x 2 / 1

= 8 moles of  KOH

molar mass KOH = 56 g/mol

mass of KOH = n x mm

mass of  KOH = 8 x 56

= 448 g of KOH 

hope this helps!

3 0
3 years ago
Read 2 more answers
W(OH)2 + 2 HCl → WCl2 + 2 H2O
Afina-wow [57]

The amount of W(OH)2 needed would be 448.126 g

<h3>Stoichiometric calculation</h3>

From the equation of the reaction:

W(OH)2 + 2 HCl → WCl2 + 2 H2O

The mole ratio of W(OH)2 to HCl is 1:2

Mole of 150g HCl = 150/36.461

                                 = 4.11 moles

Equivalent mole of W(OH)2 = 4.11/2

                                           = 2.06 moles

Mass of 2.06 moles W(OH)2 = 2.06 x 217.855

                                                = 448.188g

More on stoichiometric calculations can be found here: brainly.com/question/8062886

7 0
2 years ago
Which object traveled at a greater speed?
agasfer [191]
Object B I know it lol
5 0
3 years ago
Read 2 more answers
Of the five salts listed below, which has the highest concentration of its cation in water? assume that all salt solutions are s
Zigmanuir [339]
First of all, I need to know what these five salts are. Luckily, I found a similar problem from another website which is shown in the attached picture. The Ksp is the solubility product constant. It follows the formula:

Ksp = [cation concentration]ᵃ[anion concentration]ᵇ
where a and b are the subscripts of the metal and nonmetal, respectively. 

For the solutions ahead, let x be the concentration of the cation.

A.  The formula is PbCr₂O₄.
2.8×10⁻¹³ = [x][x]
Solving for x, x = 5.29×10⁻⁷ M

B. The formula is Co(OH)₂. 
 1.3×10⁻¹⁵ = [x][x]²
Solving for x, x = 1.09×10⁻⁵ M

C. The formula is CoS. 
 5×10⁻²² = [x][x]
Solving for x, x = 2.24×10⁻¹¹ M

D. The formula is Cr(OH)₃. 
 1.6×10⁻³⁰ = [x][x]³
Solving for x, x = 3.56×10⁻⁶ M

E. The formula is Ag₂S. 
 6×10⁻⁵¹ = [x]²[x]
Solving for x, x = 1.82×10⁻¹⁷ M

<em>Thus,the highest concentration is letter B, Cobalt (II) Hydroxide.</em>

5 0
3 years ago
Other questions:
  • Gt4rgbrbrtbr\t?<br>frehjkgbrtnvboror
    11·1 answer
  • Select the correct answer. Which of the following describes a compound? (Hint: Carbon and oxygen both appear on the periodic tab
    11·2 answers
  • What is the pH of a buffer that is 0.100 M methylamine and 0.175 M methylammonium chloride at 25 °C? pkb for methylamine = 3.36
    10·1 answer
  • How are thermal energy and mass related?
    5·2 answers
  • Calculate the pH in the titration of 25.0 mL of 0.100 M acetic acid by sodium hydroxide after the addition to the acid solution
    9·1 answer
  • Which statement best describes how an ionic bond forms?
    14·2 answers
  • The swimmer moves her hand down and to the left and her body goes forward
    11·1 answer
  • PLEASE HELP ME IM NOT SURE ABOUT THIS QUESTION
    9·1 answer
  • Select the correct answer. A solution with 117 grams of lithium hydroxide and another with 141 grams of hydrogen bromide are com
    11·1 answer
  • Question 3 of 10
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!