Answer:
28°
Step-by-step explanation:
You're given that line DE and line FG are parallel and KL and FG are perpendicular. Then you can find out angle ∠BAC by using the vertical angles property: ∠BAC=62°. Then since KL and FG are perpendicular ∠ABC = 90°. So you find the angle ∠BCA by finding the sum of interior angles: 62+90+∠BCA=180, therefore ∠BCA is 28°. Finally, ∠x or ∠JCG = 28 because ∠JCG and ∠BCA are vertical angles and congruent.
Answer:
(−3,6)
(−2,3)
(−1.2)
(0,3)
(1,6)
Step-by-step explanation:
The feasible region is shown in the picture above. The horizontal axis is the X axis.
If you now draw a family of lines parallel to 
through the region, increasing $C$, that is, the X-intercept, we will have the maximum value of $C$ when the line passes through the endpoint $(-2,6)$ .
Hence, $C=5(-2)+4(6)=14$
