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Alik [6]
3 years ago
7

Which is the solution to

Mathematics
1 answer:
enyata [817]3 years ago
5 0

Answer:

B

Step-by-step explanation:

2 x 2 = 4 - 3 = 1

4 x 2 = 8 + 3 = 11

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Which of the following equations is written in standard form?
Harlamova29_29 [7]
Standard Form is ax + by = c, where a, b, and c are not fractions and a is not negative.

So, you can go through each of your options to see which ones work with those rules. 

A. 2.5x + 3y = 12   No, this is not in Standard Form. 2.5 can be rewritten as 2<span>\frac{1}{2}, menaing A is a fraction, which you can't have.

B. -10x - 3y = 1   No, this is not in Standard Form. A is -10, but A can't be negative.

C. 2x + 3y = 12   Yes, this is in Standard Form. It follows all of the rules.

D. 5x + 5y = 10   Yes, this is in Standard Form. It follows all of the rules.

So, C and D are both written in Standard Form.


</span>
6 0
3 years ago
If a movie ticket cost $10 in 2016, what was its price in 1980
zaharov [31]

Answer:

It would be in the $3.30 or lower zone

Step-by-step explanation:

8 0
3 years ago
Y=-3(x+4)² + 1<br> Vertex to standard
Bess [88]

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Correct

Step-by-step explanation:

7 0
3 years ago
(cotx+cscx)/(sinx+tanx)
Butoxors [25]

Answer:   \bold{\dfrac{cot(x)}{sin(x)}}

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)

\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)

\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}

6 0
3 years ago
What Number must you add to complete the square?<br> x2+2x=23
Vadim26 [7]
X = {3.898979486, -5.898979486}

x = {3.9 x -5.9}
7 0
3 years ago
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