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4 years ago

The combining of one substance with another to yield a different product is the result of a(n):

Physics

2 answers:

nataly862011 [7]4 years ago

4 0

Answer is B: chemical change.

Physical, phase, and exothermic change don't form a different product.

bazaltina [42]4 years ago

4 0

Letter B. is the best answer.

I hope this answer will help you...:)

You might be interested in

Which statement best explains the relationship between the electric force between two charged objects and the distance between t

spin [16.1K]

Unfortunately, the given statements are missing from the problem. However, we can still determine the relationship between the electric force between two objects and the distance between them. The formula for the electric force is given below:

F = (k*Q1*Q2)/d^2

k is a constant, while Q1 and Q2 are the respective charges of the objects. F is force, while d is distance.

As seen in the formula, we can see that the electric force F is inversely proportional to the square of the distance between the two objects.

3 0

4 years ago

At a time when mining asteroids has become feasible, astronauts have connected a line between their 3740-kg space tug and a 5690

Gwar [14]

Answer:

61.4 s

Explanation:

The distance d₁ traveled by the asteroid:

$d_1=\frac{1}{2}a_1t^2$

The distance d₂ traveled by the space ship:

$d_2=\frac{1}{2}a_2t^2$

The total distance d:

$d=d_1+d_2=\frac{1}{2}(a_1+a_2)t^2$

Solving for time t:

$t=\sqrt{\frac{2d}{a_1+a_2}}=\sqrt{\frac{2d}{F(\frac{1}{m_1}+\frac{1}{m_2})}}=\sqrt{\frac{2dm_1m_2}{F(m_1+m_2)}}$

3 0

3 years ago

Read 2 more answers

Noah is loading the ark and the last animal on board is a stubborn 1500-kg elephant who refuses to budge. Noah and his family pu

Oxana [17]

The coefficient of sliding friction is 0.514

Explanation:

We start by writing the equations of motion of the elephant along the two directions, parallel and perpendicular, to the incline.

Along the parallel direction we have:

$F- mg sin \theta - \mu_k R = ma$ (1)

where :

F = 10,000 N is the force applied by Noah

$mg sin \theta$ is the component of the weight parallel to the incline, where:

m is the mass

g = 9.8 m/s^2 the acceleration of gravity

$\theta=10^{\circ}$ is the angle of incline

$\mu_k R$ is the force of friction, where:

$\mu_k$ is the coefficient of friction

R is the normal reaction

and a is the acceleration

Perpendicular direction:

$R-mg cos \theta =0$ (2)

where $mg cos \theta$ is the component of the weight perpendicular to the incline

From (2) we find

$R=mg cos \theta$

And substituting into (1)

$F-mg sin \theta - \mu_k mg cos \theta = ma$

We know that the elephant moves at constant speed, so the acceleration is zero:

a = 0

So the equation becomes

$F-mg sin \theta - \mu_k mg cos \theta=0$

And we can re-arrange it to find the coefficient of friction:

$F-mg sin \theta - \mu_k mg cos \theta=0\\\mu_k = \frac{F-m g sin \theta}{mg cos \theta}=\frac{10000-(1500)(9.8)(sin 10)}{(1500)(9.8)(cos 10)}=0.514$

Learn more about friction and inclined planes:

brainly.com/question/5884009

#LearnwithBrainly

4 0

3 years ago

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

masha68 [24]

Answer:

That's hilarious!! :') (Or "That eez 'ilarious!")

Explanation:

Fleur Delacour

7 0

3 years ago

A 375-g stone hangs from a thin light string that is wrapped around the circumference of a pulley with a moment of inertia of 0.

Monica [59]

Answer:

The magnitude of the acceleration of the stone is 19.87 m/s²

Explanation:

Given;

mass of stone, m = 375 g = 0.375 kg

moment of inertia, I = 0.0125 kg.m²

radius of the pulley, r = 26 cm = 0.26 m

Torque generated by the pulley on the stone is given as;

τ = F x r = Iα

where;

F is applied force on the stone due to its weight

r is the radius of the pulley

I is moment of inertia

α is angular acceleration (rad/s²)

Force, F = mg = 0.375 x 9.8 = 3.675 N

Torque, τ = F x r

τ = 3.675 x 0.26

τ = 0.9555 N.m

τ = Iα

Angular acceleration, α = τ / I

α = 0.9555 / 0.0125

α = 76.44 rad/s²

Finally, determine linear acceleration, a, in m/s²

a = αr

a = 76.44 x 0.26

a = 19.87 m/s²

Therefore, the magnitude of the acceleration of the stone is 19.87 m/s²

4 0

3 years ago