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lys-0071 [83]
4 years ago
15

What is a disruption or change that is happening to the body that causes it to sweat ?

Physics
1 answer:
ivann1987 [24]4 years ago
4 0

Answer:

the hypothalamus part of your brain sends a message to your body telling it to sweat.

When your internal temperature rises, your sweat glands release water to the surface of your skin.

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A circuit has resistors R 1 = 468 Ω and R 2 = 125 Ω R1=468 Ω and R2=125 Ω , and two batteries V 1 = 12.0 V and V 2 = 3.00 V V1=1
Greeley [361]

Answer:

0.0192A

Explanation:

Since, the reading of the galvanometer is 0 A, the voltage across the resistance R will be:

Step 1

VR = V2

VR = 3.00v

Step 2

Calculating the current through the resistance R as below,

IR = V1 - V2 /R1

IR = 12 - 3 /468

IR =0.0192A

7 0
4 years ago
Three small balls of the same size but different masses are hung side-by-side in parallel on the strings of same length. They to
andrey2020 [161]

Answer:

m1/6 ( c )

Explanation:

since all the balls starts having the same momentum after the two collisions we will apply the principal of conservation of energy

After first collision

m1v = m1v1 + m2v2 --- ( 1 )

After second collision

m2v2 = m2v2 + m3v3   ---- ( 2 )

combining equations 1 and 2

m1v = m1v1 + m2v2 + m3v3  ----- ( 3 )

All balls moving at the same momentum ( p ) = m1v1 = m2v2 = m3v3

note ; 3p = m1v ∴ m3 = \frac{m1v}{3v3}  -----  ( 4 )

applying conservation of energy

3v = v1 + v2 + v3 ------- ( 5 )

also 3m1v1 = m1v = v1 = v/3 =

v2 + v3 = 8/3 v ----- ( 6 )

next eliminate V3 for equation 6 by applying conservation of energy and momentum

m1 =  2m2 ------ ( 7 )

now using p1 = p2 = m1v1 = 1/2 m1v1  hence v2 = 2v1  where v1 = 1/3 v

hence ; v2 = 2/3 v ------- ( 8 )

solving with equation 6 and 8

v3 = 2v ------ ( 9 ) ∴  v/v3 = 1/2 ---- ( 10 )

solving with equation 9 and 10

m3 = m1/3 * 1/2 = m1/6

8 0
3 years ago
A person’s willingness to respond to a particular stimulus is called __________.
Reil [10]
C), stimuli adaption. 
7 0
4 years ago
Read 2 more answers
Several different compounds can share the same empirical formula. The Molecular weight for three compounds with the empirical fo
Pie

Molecular formulas:

  1. CH₂O;
  2. C₂H₄O₂;
  3. C₆H₁₂O₆.
<h3>Explanation</h3>

The empirical formula of a compound tells only the ratio between atoms of each element. The empirical formula CH₂O indicates that in this compound,

  • for each C atom, there are
  • two H atoms, and
  • one O atom.

The molecular weight (molar mass) of the molecule depends on how many such sets of atoms in each molecule. The empirical formula doesn't tell anything about that number.

It's possible to <em>add</em> more of those sets of atoms to a molecular formula to increase its molar mass. For every extra set of those atoms added, the molar mass increase by the mass of that set of atoms. The mass of one mole of C atoms, two mole of H atoms, and one mole of O atoms is 12.0 + 2\times 1.0 + 16.0 = 30.0\;\text{g}.

  • CH₂O- 30.0 g/mol;
  • C₂H₄O₂- 30.0 + 30.0 = 2 × 30.0 = 60.0 g/mol;
  • C₃H₆O₃- 30.0 + 30.0 + 30.0 = 3 × 30.0 = 90.0 g/mol.

It takes one set of those atoms to achieve a molar mass of 30.0 g/mol. Hence the molecular formula CH₂O.

It takes two sets of those atoms to achieve a molar mass of 60.0 g/mol. Hence the molecular formula C₂H₄O₂.

It takes \dfrac{180.0}{30.0} = 6 sets of those atoms to achieve a molar mass of 180.0 g/mol. Hence the molecular formula C₆H₁₂O₆.

5 0
3 years ago
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Two objects have a certain gravitational force between them. What would happen if the mass of one of the objects suddenly increa
ludmilkaskok [199]
Your answer would be A.
7 0
3 years ago
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