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lina2011 [118]
3 years ago
14

Which of the following are ohmic materials? a. Batteries Wires Resistors Light bulb filaments b. Batteries, wires, resistors, an

d light bulb filaments c. Wires and resistors Batteries and wires d. Batteries, wires, resistors, light bulb filaments, and semiconductors
Physics
1 answer:
Bingel [31]3 years ago
6 0

Answer:

A., B., and C.

Explanation:

An Ohmic material is a material that obeys Ohm's Law, V = IR.

In contrast, a non-Ohmic material is one that does not obey Ohm's law.

Ohm's law states that the voltage across an electrical object is proportional to the current flowing through it, with the constant of proportionality being Resistance, R (in Ohm's).

The only Non-Ohmic material is the semiconductor, as semiconductors do not obey Ohm's law.

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Imagine that you're standing in a large room when a loud noise is made. You begin hearing a series of echoes. Which characterist
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It is generally a good idea to gain an understanding of the "size" of units. Consider the objects listed and calculate the magni
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Answer:

Explanation:

The standard unit of momentum Is kgm/s

And momentum is the product of mass and velocity

Then,

Momentum = mass × velocity

P = mv

Where

m is mass in kg

v is velocity in m/s

Now,

Given that,

M = 31.8mg

1mg = 10^-3g

So, m = 31.8 × 10^-3g

Also, 1000g = 1kg → 1g = 10^-3 kg

So,

m = 31.8 × 10^-3 × 10^-3kg

m = 31.8 × 10^-6 kg

v = 2.53mi/hr

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Then,

v = 2.53 × 1609.34m/ 3600s

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So, momentum is given as

P = mv

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3 years ago
A 0.30-kg flying pig toy is attached to the ceiling with a string. When the pig’s wings flap, it moves at a constant speed of �
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Answer:

58.5 deg

Explanation:

v = mass of the pig toy = 0.30 kg

v = speed of the toy = 2 m/s

r = radius of the circle = 0.25 m

\theta = Angle of the string with the vertical = ?

T = Tension force in the string

Using equilibrium of force in vertical direction

T Cos\theta = mg                                     eq-1

Along the horizontal direction, the component of tension force provides the necessary centripetal force, hence

T Sin\theta = \frac{mv^{2}}{r}                                  eq-2

Dividing eq-2 by eq-1

\frac{T Sin\theta}{T Cos\theta} = \frac{\frac{mv^{2}}{r}}{mg}

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Which type of bond shows two or more atoms sharing electrons?
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