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2 years ago

Given that f(x)=2x+2 evaluate f(1)+f(5)

Mathematics

2 answers:

Svetlanka [38]2 years ago

8 0

Answer:

Step-by-step explanation:

To solve this, you need to evaluate the function at f(1), which just means that you have to plug in 1 for any x you see in the equation. For example, here f(1) = 2(1) + 2 which simplifies to 4. Next find f(5). By doing the same process you will find that this is 12. The problem asks for f(1) + f(5) so by putting those values in you will get 4+12=16. Hope this helps! :)

tankabanditka [31]2 years ago

6 0

Answer:

F(x) = 2x + 2 is the equation given.

We are going to solve this one after the other i.e solving for f(1) 1st amd then f(5) and later adding the two together.

Solving for F(1)

F(x)= 2x + 2

This means that you substitute 1 for x in the equation.

F(1) = 2(1) + 2

= 2 + 2

= 4.

For F(5)

You substitute 5 for x in the same equation.

That is,

F(5) = 2(5) + 2

= 10 + 2

= 12

now F(1) + F(5)

= 4 + 12

= 16

Step-by-step explanation:

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90 x= 81 + 25 I need help ?

charle [14.2K]

Answer:

$x = \frac {53} {45}$

Step-by-step explanation:

Step 1: Combine on the right side

$90x = 81 + 25$

$90x = 106$

Step 2: Divide both sides by 90

$\frac {90x} {90} = \frac {106} {90}$

$x = \frac {106/2} {90/2}$

$x = \frac {53} {45}$

Answer: $x = \frac {53} {45}$

4 0

3 years ago

Read 2 more answers

How do measurements of time differ for events in a frame of reference that moves at 50% of the speed of light relative to us? At

ZanzabumX [31]

Answer with explanation:

Relation between Speed , Distance and time

Distance =Speed × Time

→It means Speed is inversely Proportional to time.

As distance will remain constant , in that frame of reference

If speed of light in a Medium

$=s=3 \times 10^8 \frac{\text{meter}}{\text{second}}$

Then, time taken to cross the medium = t seconds or hours or another unit of time.

Now, If speed of light is 50% of the speed of light relative to us

That is Speed of light in another medium

$=w=\frac{50}{100} \times 3 \times 10^8\\\\=1.5 \times 10^8 \frac{\text{meter}}{\text{second}}$

Then, time taken to cross the medium = 2t seconds or hours or another unit of time.

Using Unitary Method

$\rightarrow v_{1}\times t_{1}=v_{2} \times t_{2}\\\\1.\rightarrow 3 \times 10^8 \times t=\frac{50}{100} \times 3 \times 10^8 \times t_{1}\\\\t_{1}=2t\\\\2.\rightarrow 3 \times 10^8 \times t=\frac{99.5}{100} \times 3 \times 10^8 \times t_{2}\\\\t_{2}=\frac{1000t}{995}\\\\t_{2}=\frac{200t}{199}$