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Assoli18 [71]
3 years ago
12

when 10.00 g of phosphorus reacts with oxygen, it produces 17.77 g of a phosphorus oxide. This phosphorus oxide was found to hav

e a molecular mass of approximately 220 g/mole. Determine the molecular formula.
Chemistry
1 answer:
Alex_Xolod [135]3 years ago
8 0

Answer:

Molecular formula = P₄O₆

Explanation:

P(s)         +        O₂(g)------------------------------------⇒ PₓOₙ (g)

10g                     (17.77-10)g                                    17.77g

10g                        7.77g                                          17.77g  (gramme ratio)

The molecular mass of Phosphorus  (P) = 31g/mole

The molecular mass of Oxygen atom (O) = 16g/mole

Mole ratio is given by:

P              :             O

10/31                    7.77/16

0.3226       :         0.4856                Mole ratio---------------------------- (1)

Divide (1)  through by 0.3226

 1                 :        1.5-------------------------------------------- (2)

From  (2), the empirical formula for Phosphorus oxide :

Empirical formula = P₁O₁.₅

                               =  PO₁.₅

The molecular formula can be calculated from below:

Since the molecular formula is a multiple of the empirical formula we have

Molecular formula = (PO₁.₅)ₙ----------------------------------- (3)

Since we are given the molecular mass of the oxide formed, we have:

(PO₁.₅)ₙ = 220-----------------------------(4)

[31 + (16 x 1.5)] x n = 220

[31 + 24]n = 220

55n =220

n = 4

Substituting into (3), we have :

Molecular formula = (PO₁.₅)₄

                               = P₄O₆

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what do the presence of fish and a wide diversity of invertebrates in a river indicate regarding water quality?
astra-53 [7]
It indicates that the river water is very good quality with nutrients and minerals to support an ecosystem.
7 0
3 years ago
A certain ore is 24.3% nickel by mass. how many kilograms of this ore would you need to dig up to have 55.0 g of nickel?
zysi [14]
Let x be the mass of the ore in grams such that the equation that would allow us to answer this item would be,

                     55 = (x)(0.243)

The value of x is calculated as,

                 x = 55/0.243
                   x = 226.337 grams

Then, solve for amount in kilograms by dividing the calculated value by 1000. This methodology will give us an answer of 0.226337. Hence, the answer is 0.226. 


4 0
3 years ago
The total pressure in a tank is filled with a mixture of gases : Oxygen, Helium, and Argon is 15.3 atm. The P(He) = 3.2 atm, P(O
Viktor [21]

Answer:

4.7 atm

Explanation:

From the question given above, the following data were obtained:

Total pressure (P) = 15.3 atm

Pressure of Helium, P(He) = 3.2 atm

Pressure of Oxygen, P(O) = 7.4 atm

Pressure of Argon, P(Ar) =?

The pressure of Argon, P(Ar) in the tank can be obtained as illustrated below:

P = P(He) + P(O) + P(Ar)

15.3 = 3.2 + 7.4 + P(Ar)

15.3 = 10.6 + P(Ar)

Collect like terms

15.3 – 10.6 = P(Ar)

4.7 = P(Ar)

P(Ar) = 4.7 atm

Therefore, the pressure of Argon, P(Ar) in the tank is 4.7 atm

4 0
3 years ago
The table shows the number of charged subatomic particles in an ion.
Anarel [89]

Answer:

The ion will repel the substance because it has lost two electrons.

Explanation:

An ion is a charged specie. We can see from the question that the ion has twelve positive and ten negative particles.

If there are more positive particles than negative particles, then the ion is positively charged.

If the ion is positively charged, it will repel another positively charged particle because like charges repel while opposite charges attract.

3 0
3 years ago
A reaction will be spontaneous only at low temperatures if both ΔH and ΔS are negative. For a reaction in which ΔH = −310.1 kJ/m
ruslelena [56]

Answer:

3211.12 K

Explanation:

The expression for the standard change in free energy is:

\Delta G=\Delta H-T\times \Delta S

Where,  

\Delta G is the change in the Gibbs free energy.

T is the absolute temperature. (T in kelvins)

\Delta H is the enthalpy change of the reaction.

\Delta S is the change in entropy.

For reaction to be spontaneous, \Delta G

Given, \Delta H=-310.1\ kJ/mol=-310100\ J/mol

\Delta S=-89.00\ J/K.mol

So,

\Delta H-T\times \Delta S

Thus, applying values as:-

-310100-T\times (-89.00)

So, T = 3484.27 K

The conversion of T( °C) to T(K) is shown below:

T( °C)  = T(K) - 273.15  

So,  

T = (3484.27 - 273.15) K = 3211.12 K

<u>The temperature below which the reaction is spontaneous is:- 3211.12 K </u>

6 0
3 years ago
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