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Aleonysh [2.5K]
2 years ago
14

Determine the total net force and the direction of movement for the situation.

Chemistry
1 answer:
k0ka [10]2 years ago
6 0

Answer:

well it can be 11 or 16n

Explanation:

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Which of the following statements about the combustion of glucose with oxygen to form water and carbon dioxide (C6H12O6 + 6 O2 →
worty [1.4K]

Answer:

The correct statement is:

E - The entropy of the products is greater than the entropy of the reactants.

Explanation:

C₆H₁₂O₆ + 6 O₂ → 6 CO₂ + 6 H₂O

As glucose is a large molecule and then it is transformed into many molecules of water and carbon dioxide, the entropy of the system increases. If the number of molecules increases, the disorder increases.

Initial state: 7 molecules (1 glucose + 6 oxygen)

Final state: 12 molecules (6 carbon dioxide + 6 water)

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3 years ago
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Which of the following vary for isotopes of atoms of the same element?
cupoosta [38]

Answer:

The answer is B. Atomic Mass

7 0
2 years ago
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How to put Roman numerals in a science equation
Bogdan [553]
Example:

Oxygen(III)
6 0
3 years ago
What effect does supercritical mass have on a nuclear reaction?
Ksju [112]
Supercritical mass results to an increase in the rate of fission. There is a chain reaction that will occur. Nuclear fission or explosion used in atomic bombs relies on supercritical mass. An atom splits into two, with each splitting into two pairs and so on, releasing energy in each step.
3 0
3 years ago
Read 2 more answers
Pls help me with this
Zina [86]

Answer:

[I_2]=[Br]=0.31M

Explanation:

Hello there!

In this case, according to the given information, it is possible for us to set up the following chemical equation at equilibrium:

I_2+Br_2\rightleftharpoons 2IBr

Now, we can set up the equilibrium expression in terms of x (reaction extent) whereas the initial concentration of both iodine and bromine is 0.5mol/0.250L=2.0M:

K=\frac{[IBr]^2}{[I_2][Br_2]} \\\\1.2x10^2=\frac{(2x)^2}{(2.0-x)^2}

Thus, we solve for x as show below:

\sqrt{1.2x10^2} =\sqrt{\frac{(2x)^2}{(2.0-x)^2}} \\\\10.95=\frac{2x}{2.0-x}\\\\21.91-10.95x=2x\\\\21.91=12.95x\\\\x=\frac{21.91}{12.95} \\\\x=1.69M

Therefore, the concentrations of both bromine and iodine are:

[I_2]=[Br]=2.0M-1.69M=0.31M

Regards!

8 0
3 years ago
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