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Aloiza [94]
3 years ago
14

Determine the value for the following reaction.

Chemistry
1 answer:
Stells [14]3 years ago
7 0

Answer:

ΔH = -22 kcal

Step-by-step explanation:

N₂(g) + 3H₂(g) ⇌ 2NH₃(g) + 22 000 cal

Energy is on the right-hand side of the equation, so it is being <em>released</em> by the system.

The thermodynamic convention is that <em>energy going out of a system is negative.</em> Thus,

ΔH = -22 000 cal     Convert to kilocalories

ΔH = -22 kcal

A and B are both wrong, because you divide by 1000 to convert calories to kilocalories.

C is wrong, because the sign must be negative for an exothermic reaction.

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Why should you be careful when you heat your NaCl solution to evaporate the water?
ivolga24 [154]

Answer & Explanation:

  • If we heat the NaCl solution strongly, it boils and moves vigorously causing some of the solution to get out of the container.
  • This will cause loss of NaCl in the amount that get out of the container.
  • So, this affect the yield of the obtained NaCl after water evaporation.
7 0
4 years ago
Consider the heating curve for water. A graph of the heating curve for water has time in minutes on the horizontal axis and Temp
Zolol [24]

Answer:

0°C.

Explanation:

Hello,

In this case, given the heating curve of water on the attached document, we can notice that at 0 °C the solid starts melting, which means that the melting point is reached. Melting point is known as a physical change whereby a solid changes to liquid by the addition of heat as it allows the molecules to separate to each other.

Best regards.

4 0
4 years ago
What type of bond would form between two atoms of selenium? A. Double ionic bond B. Single ionic bond C. Single covalent bond D.
kirill115 [55]

The corret answer is D

3 0
4 years ago
La densidad del óxido de magnesio. MgO, es de 3.581 g/cm3 El MgO, es de 3.581 g/cm3 El MgO cristaliza con ordenamiento cúbico co
Jobisdone [24]

Answer:

a=4.213cm

r=1.490x10^{-8}cm

Explanation:

Hola.

En este caso, para calcular la longitud (a) de una cara de celda unitaria, consideramos la siguiente ecuación:

\rho =\frac{#at*M}{a^3N_A}

En la que consideramos el número de átomos por celda (4 para FCC), la masa molar (40.3 g/mol para MgO) y el número de avogadro para obtener:

3.581g/mol = \frac{4atom/celda*40.3g/mol}{a^3*6.02x10^{23}atom/mol}

Despejando para a, obtenemos:

a^3 = \frac{4atom/celda*40.3g/mol}{3.581g/cm^3*6.02x10^{23}atom/mol}\\\\a=\sqrt[3]{7.478cm^3} \\\\a=4.213cm

Finalmente, el radio lo calculamos como:

r=\frac{\sqrt{2}*a}{4}=\frac{\sqrt{2}*4.213x10^{-8}cm}{4}\\\\r=1.490x10^{-8}cm

¡Saludos!

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4 years ago
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Answer:

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Explanation:

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