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Jlenok [28]
3 years ago
7

Calculate the volume of this irregular solid to the nearest cubic centimeter​

Chemistry
2 answers:
EleoNora [17]3 years ago
6 0

Answer:

8 cm3

Explanation:

The volume of this irregular solid will calculated as the difference between the final volume and the initial volume;

The final volume of the water and the solid is 25 ml

The initial volume of the water alone was 17 ml

The volume of the irregular solid is thus approximately;

25 - 17 = 8 ml

We then use the conversion;

1 cm3 = 1 mL

Thus the volume of the solid is 8 cm3

oee [108]3 years ago
3 0

Answer:

8

Explanation:

took the assignment

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This is the chemical formula for talc Mg3(Si2O5)2(OH)2(the main ingredient in talcum powder):
Elena-2011 [213]

Answer:

0.022 mol O

Explanation:

Mg3(Si2O5)2(OH)2

We can see that 1 mol of this substance has 3 mol of Mg.

Oxygen altogether  is 5*2 (from (Si2O5)2) + 2(from(OH)2) = 10 +2 = 12

So, 1 mol of this substance has 12 mol oxygen.

So,  1 mol of this substance contains 3 mol Mg and  12 mol O, or

ratio Mg : O = 3 : 12 = 1 : 4

1 mol Mg ----- 4 mol O

0.055 mol Mg ---x mol O

x = 0.055*4/1 = 0.220 mol O

8 0
3 years ago
WILL GIVE BRAINLYLEST ANSWER!! You discover a new and strange liquid. It has the mass of 70 g and volume of 84 mL. Will the liqu
Karo-lina-s [1.5K]

Answer: The strange liquid would float to the top of a cup of water.

Explanation:

Density = Mass/Volume

Strange Liquid Density = 70g/84mL

Strange Liquid Density = 0.833g/mL

Density of water in g/mL = 1 g/mL

Strange Liquid Density < Water Density

A substance with a lower density would be suspended above a substance with a higher density.

Since the density of the strange liquid is less than that of water, it would float to the top of a cup of water.

3 0
3 years ago
What is the maximum volume of a 0.788 M CaCl2 solution that can be prepared using 85.3 g CaCl2?
Law Incorporation [45]
The answer is 0.975 L

Volume = mol/Molarity

We have molarity (0.788 M) and we need mol and volume. Let's first calculate number of moles of CaCl2 in 85.3 g:

Molar mass of CaCl2 is sum of atomic masses of Ca and Cl:
Mr(CaCl2) = Ar(Ca) + 2Ar(Cl) = 40 + 2 * 35.45 = 40 + 70.9 = 110.9 g/mol

So, if 110.9 g are in 1 mol, 85.3 g will be in x mol:
110.9 g : 1 mole = 85.3 g : x
x = 85.3 g * 1 mole / 110.9
x = 0.769 moles

Now, calculate the volume:
V = 0.769/0.788
V = 0.975 L
5 0
3 years ago
An atom of 70kr has a mass of 69. 955264 amu. mass of1h atom = 1. 007825 amu mass of a neutron = 1. 008665 amu. calculate the bi
Leno4ka [110]

The binding energy in MeV per atom is - 63284.56 Mev.

The amount of energy needed to detach a particle from a system of particles or to disperse every particle in the system is known as the binding energy. Subatomic particles in atomic nuclei, electrons attached to atom's nuclei, and atoms and ions bonded together in crystals are three examples of where binding energy is very relevant.

If we have a nucleus with Z protons and N neutrons and mass MA, where A = Z + N then its binding energy in MeV is given by: Eb(MeV) = (Zmp + Nmn - MA) x 931.494 MeV/u

Mass of atom = 69.955264 amu

Mass of proton = 1.007825 amu

Mass of neutron = 1.008665 amu

Binding energy, Mev = (Zmp + Nmn - M) × 931.494MeV/u

                                    = ( 1.007825 + 1.008665 -  69.955264) × 931.494

                                    = - 67.938774 × 931.494

                                    = - 63284.56 Mev

Therefore, the binding energy in MeV per atom is - 63284.56 Mev.

Learn more about binding energy here:

brainly.com/question/16795451

#SPJ4

3 0
1 year ago
How many moles of lithium metal would need to react with excess oxygen gas to produce 4 moles of lithium oxide in the following
Oduvanchick [21]
4Li + O₂ = 2Li₂O

Li : Li₂O = 4 : 2 = 2 : 1

2 : 1
x : 4

x=4*2/1=8 mol

D) 8
6 0
2 years ago
Read 2 more answers
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