First, if you want to get the amount of production from the equation, you need to use the units of mol. So, we need to know the molar mass of C which is 15.75/12=1.31 mol. Then we need to use the less part(O2) to get the production amount which is 0.116 mol. Then we can get the answer in units of g: 0.116*(12+16*2)=5.104 g.
Plagiarism is when you just copy exactly what someone else says, without their permission, or without citing where you got it from.
Common knowledge should be your own words. unless you take it from somewhere else, it doesnt need anything.
1) Chemical equation:
Mg + I2 ---> Mg I2
2) molar ratios
1 mol Mg : 1 mol I2 : 1 mol Mg I2
3) Calculate the number of moles of Mg in 48 grams
Atomic mass of Mg: 24.3 g/mol
number of moles = mass in grams / atomic mass = 48 g / 24.3 g/mol = 1.975 mol Mg
4) Use a proportion with the molar ratios
1 mol I2 / 1 mol Mg = x / 1.975 mol Mg =>
=> x = 1 mol I2 * 1.975 mol Mg / 1 mol Mg = 1.975 mol I2
5) Convert 1.975 mol I2 to grams
molar mass of I2 = 2 * 126.9 g/mol = 253.8 g/mol
mass = number of moles * molar mass = 1.975 mol * 253.8 g/mol = 501.255 g
Answer: 501 grams
The oxidation half equation is Zn ------> Zn^2+ + 2e while the reduction half equation is Cu^2+ + 2e------> Cu.
A redox reaction is a reaction in which there is a loss/gain of electrons. The specie that gives out electrons experiences an increase in oxidation number while the specie that gains the electrons experiences a decrease in oxidation number.
For the reaction; CuCl2 + Zn → ZnCl2 + Cu
The oxidation half equation is;
Zn ------> Zn^2+ + 2e
The reduction half equation is;
Cu^2+ + 2e------> Cu
The chloride ion is excluded because its oxidation number does not change from left to right in the reaction.
Learn more: brainly.com/question/967776
