Answer:
Products will be K2SO4 and Cu(NO3)2. A precipitate will not form.
Explanation:
Double replacement reactions are the switching of cations between two compounds. So in this case, the K+ and Cu 2+ cations will switch places.
KNO3 + CuSO4 -> K2SO4 + Cu(NO3)2
According to solubility rules, any substances containing NO3 or a Group 1 ion (K+ in this case) will be definitely soluble. There are a few exceptions to the Group 1 rule but it does not apply here. Potassium sulfate (K2SO4) contains a Group 1 ion so it will be soluble and not be a precipitate. And copper nitrate (Cu(NO3)2) contains nitrate so it will also be soluble and not be a precipitate.
Answer is: 0.330 ppm
Hope this helps
Answer:
The partial pressure in mm Hg for each of the species are:
PCO = 0
PH2 = 3874
PCH3OH = 347
The total pressure is 4221
Explanation:
We have to use Ideal gas equation PV = nRT and Partial pressure rule Total Pressure= ∑ Partial pressures.
We have following data:
T= 357K (85+272); nCO=0.078 (2.2/28); nH2 = 2.43 (4.86/2); R=62.36
With equation CO(g) + 2 H2(g) → CH3OH(g) we can calculate the amount of moles the reaction has finished. The limit reagent is CO because is consumed completely and moles CO in flask are 0. According to equation, every CO mol produces one CH3OH mol. That means 0.078 CO moles produces 0.078 CH3OH moles. From Ideal gas equation we have P=nRT/V.
Applying:
PH2=0.87*62.36*357/5=3874
PCH3OH =0.078*62.36*357/5=347
Total P = 3874+347=4221
I hope my answer helps you
