First, if you want to get the amount of production from the equation, you need to use the units of mol. So, we need to know the molar mass of C which is 15.75/12=1.31 mol. Then we need to use the less part(O2) to get the production amount which is 0.116 mol. Then we can get the answer in units of g: 0.116*(12+16*2)=5.104 g.
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Common knowledge should be your own words. unless you take it from somewhere else, it doesnt need anything.
1) Chemical equation:
Mg + I2 ---> Mg I2
2) molar ratios
1 mol Mg : 1 mol I2 : 1 mol Mg I2
3) Calculate the number of moles of Mg in 48 grams
Atomic mass of Mg: 24.3 g/mol
number of moles = mass in grams / atomic mass = 48 g / 24.3 g/mol = 1.975 mol Mg
4) Use a proportion with the molar ratios
1 mol I2 / 1 mol Mg = x / 1.975 mol Mg =>
=> x = 1 mol I2 * 1.975 mol Mg / 1 mol Mg = 1.975 mol I2
5) Convert 1.975 mol I2 to grams
molar mass of I2 = 2 * 126.9 g/mol = 253.8 g/mol
mass = number of moles * molar mass = 1.975 mol * 253.8 g/mol = 501.255 g
Answer: 501 grams
The oxidation half equation is Zn ------> Zn^2+ + 2e while the reduction half equation is Cu^2+ + 2e------> Cu.
A redox reaction is a reaction in which there is a loss/gain of electrons. The specie that gives out electrons experiences an increase in oxidation number while the specie that gains the electrons experiences a decrease in oxidation number.
For the reaction; CuCl2 + Zn → ZnCl2 + Cu
The oxidation half equation is;
Zn ------> Zn^2+ + 2e
The reduction half equation is;
Cu^2+ + 2e------> Cu
The chloride ion is excluded because its oxidation number does not change from left to right in the reaction.
Learn more: brainly.com/question/967776