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TEA [102]
3 years ago
13

Calculate the amount of carbon dioxid gas in 1.505x10^23 molecules of the gas.

Chemistry
1 answer:
Daniel [21]3 years ago
4 0

Explanation:

  • We need to find the amount of carbon dioxide gas in 1.505\times 10^{23} molecules of the gas.
  • We know that, 1 mole weighs 44 gram of carbon dioxide which contains 6.022\times 10^{23} number of molecules. It means that, 6.022\times 10^{23} number of molecules present in 44 grams of carbon dioxide molecule. So,1.505\times 10^{23}  number of molecules present in :

=\dfrac{1.0505\times 10^{23}}{6.022\times 10^{23}}\times 44\\\\=7.675\ \text{grams}

  • Hence, 7.675 grams of carbon dioxide is present in 1.505\times 10^{23} molecules of the gas.
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