Answer:
As you go down a group on the periodic table, you get more electron shells and therefore a larger atomic radius.
The wavelength of the light is 6.00 × 10^(-5) m.
The formula connecting frequency <em>f</em> and wavelength λ is
<em>f</em>λ = <em>c</em>
where <em>c</em> = the speed of light [2.998 × 10^8 m·s^(-1)]
We can rearrange the formula to get
λ = <em>c</em>/<em>f
</em>
∴ λ = 2.998 × 10^10 m·s^(-1)/5.00 × 10^12 s^(-1) = 6.00 × 10^(-5) m = 60.0 µm
Answer:
d. 103.3
Explanation:
In the given question, the National Weather Service routinely supplies atmospheric pressure data to help pilots set their altimeters. And the units of atmospheric pressure used for reporting the atmospheric pressure data are inches of mercury. For a barometric pressure of 30.51 inches of mercury, we can calculate the pressure in kPa as follow:
In principle, 3.386 kPa is equivalent to the atmospheric pressure of 1 inch of mercury. Thus, 30.51 inches of mercury is equivalent to 30.51 in *(3.386 kPa/1 in) = 103.307 kPa.
Therefore, a barometric pressure of 30.51 inches of mercury corresponds to _____103.3_____ kPa.
Answer:
0.99 m³
Step-by-step explanation:
This looks like a case where we can use the <em>Combined Gas Law </em>to calculate the volume
p₁V₁/T₁ = p₂V₂/T₂ Multiply both sides by T₁
p₁V₁ = p₂V₂T₁/T₂ Divide each side by p₁
V₁ = V₂ × p₂/p₁ × T₁/T₂
<em>Data:
</em>
p₁ = 201 kPa; V₁ = ?; T₁ = 27 °C = 300.15 K
p₂ = 2.5 kPa; V₂ = 59.3 m³; T₂ = -14 °C = 223.15 K
<em>Calculation:
</em>
V₁ = 59.3 × 2.5/201 × 300.15/223.15
V₁ = 20 × 0.0124 × 1.345
V₁ = 0.99 m³
Answer:
an Additional shell
Explanation:
Potassium has an additional energy level when compared to sodium. This is due to an extra shell added. In the periodic table when you go down the group, the atomic radius increases due to increasing energy levels.
The atomic radius mean the distance from the center of the nucleus to the valance shell. it actually describes the size of the atom