Question

Calculate the amount of carbon dioxid gas in 1.505x10^23 molecules of the gas.

Answer 1

Explanation:

• We need to find the amount of carbon dioxide gas in $1.505\times 10^{23}$ molecules of the gas.

• We know that, 1 mole weighs 44 gram of carbon dioxide which contains $6.022\times 10^{23}$ number of molecules. It means that, $6.022\times 10^{23}$ number of molecules present in 44 grams of carbon dioxide molecule. So,$1.505\times 10^{23}$  number of molecules present in :

$=\dfrac{1.0505\times 10^{23}}{6.022\times 10^{23}}\times 44\\\\=7.675\ \text{grams}$

• Hence, 7.675 grams of carbon dioxide is present in $1.505\times 10^{23}$ molecules of the gas.