There are two ways to solve this problem. We can use the ICE method which is tedious and lengthy or use the Henderson–Hasselbalch equation. This equation relates pH and the concentration of the ions in the solution. It is expressed as
pH = pKa + log [A]/[HA]
where pKa = - log [Ka]
[A] is the concentration of the conjugate base
[HA] is the concentration of the acid
Given:
Ka = 1.8x10^-5
NaOH added = 0.015 mol
HC2H3O2 = 0.1 mol
NaC2H3O2 = 0.1 mol
Solution:
pKa = - log ( 1.8x10^-5) = 4.74
[A] = 0.015 mol + 0.100 mol = .115 moles
[HA] = .1 - 0.015 = 0.085 moles
pH = 4.74 + log (.115/0.085)
pH = 4.87
Answer: X: High and Y: High
Explanation: When comparing plasma with solids it is seen that solids are more denser than plasma and has less kinetic energy as compared to plasma.
So among the difference plasma will have high kinetic energy and solids will have high density in comparison with each other.
Answer:
T = 525K
Explanation:
The temperature of the two-level system can be calculated using the equation of Boltzmann distribution:
(1)
<em>where Ni: is the number of particles in the state i, N: is the total number of particles, ΔE: is the energy separation between the two levels, k: is the Boltzmann constant, and T: is the temperature of the system </em>
The energy between the two levels (ΔE) is:
<em>where h: is the Planck constant, c: is the speed of light and k: is the wavenumber</em>
Solving the equation (1) for T:
<em>With Ni = N/3 and k = 1.38x10⁻²³ J/K, </em><em>the temperature of the two-level system is:</em><em> </em>
I hope it helps you!
