Answer:
1. -4
2. +1
3. 0
4. +4
5. -2
6. +1
7. -2
reduced = H
oxidized = O
Explanation:
Know oxidation rules. 
- Hope this helped! Please let me know if you would like to learn this. I could show you the rules and help you work through them.
 
        
             
        
        
        
Answer:
All bonds are equivalent in length and strength within the molecule.
Gaseous SO3 is a trigonal planar molecule that exhibit a D3h symmetry group.
Sulfur has sp2 hybridization and it has 6 outer electrons which make the bonds with the oxygen.
Its constituent sulfur atom has an oxidation state of +6 and a formal charge of 0. 
The Lewis structure is made up of one S=O double bond and two S–O dative bonds that doesn't not engage the d-orbitals. ( Thus, SO3 molecule has three double bonded oxygen to the central sulfur atom). This explains the strength.
It gaseous form had a zero electrical dipole moment  because of the 120° angle between the S-O bonds.
Explanation:
 
        
             
        
        
        
I believe a possible Lewis dot structure that does not obey the octet rule, where all elements are required to have 8 electrons in their outermost shell, would be the SF4 molecule. 
Sulfur can contain an more than 8 electrons, in this molecule and thus has an expanded octet.