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3 years ago

What is the correct way to show carbon dioxide in the gas phase?

1 answer:

8 0

The correct way of showing carbon dioxide in the gas phase is b. CO2 (g)

This notation is commonly used in showing chemical reactions wherein the phases of the constituents are important. Gases are denoted by (g), solids are denoted by (s), and liquids are denoted by (l). Aqueous solutions are also denoted (aq).

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How many moles of water would form the reaction of exactly 58.3 grams of magnesium hydroxide

Marat540 [252]

Answer:

$\boxed{\text{2.00 mol}}$

Explanation:

We know we will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

You don't tell us what the reaction is, but we can solve the problem so long as we balance the OH.

M_r: 58.32

Mg(OH)₂ + … ⟶ … + 2HOH

m/g: 58.3

(a) Moles of Mg(OH)₂

$\text{Moles of Mg(OH)$_{2}$} =\text{58.3 g Mg(OH)$_{2}$} \times \dfrac{\text{1 mol Mg(OH)$_{2}$}}{\text{58.32 g Mg(OH)$_{2}$}}\\\\=\text{0.9997 mol Mg(OH)$_{2}$}$

(b) Moles of H₂O

The molar ratio is 2 mol H₂O = 1 mol Mg(OH)₂.

$\text{Moles of H$_{2}$O}= \text{0.9995 mol Mg(OH)$_{2}$} \times \dfrac{\text{2 mol {H$_{2}$O}}}{ \text{1 mol Mg(OH)$_{2}$}}\\\\= \textbf{2.00 mol H$_{2}$O}$

The reaction will form $\boxed{\textbf{2.00 mol}}$ of water.

6 0

3 years ago

The answer to this question

Ulleksa [173]

Hey there!

Oxygen needs two bonds to have a valence orbital of s²p⁶.

In a hexanal molecule, oxygen has a double bond with one carbon atom.

A double bond is when two pairs of electrons are being shared.

So your answer is b. 2.

Hope this helps!

7 0

3 years ago

Adding a neutron to an atom changes what property of the atom?

brilliants [131]

Since the atomic mass consists of protons and neutrons, that would be the answer.

Answer: <span>C. the atomic mass </span>

3 0

3 years ago

In an atom, electrons ____.

irakobra [83]

In an atom, electrons travel outside the nucleus.

c. travel outside the nucleus.

7 0

3 years ago

A 50 gram sample of a radioisotope undergoes 2 half-lives. How many grams

Veseljchak [2.6K]

Answer:

At the end of second half life 12.5 g will left

Explanation:

Given data:

Total Mass = 50 g

Half lives = 2

Mass remain at the end = ?

Solution:

At time zero = 50 g

At 1st half life = 50 g /2 = 25 g

At second half life = 25 g/2 = 12.5 g

So at the end of second half life 12.5 g will left.

3 0

3 years ago